SAMACHEER KALVI MATH SOLUTION FOR EXERCISE 3.3 PART 4

This page Samacheer Kalvi Math Solution for Exercise 3.3 part 4 is going to provide you solution for every problems that you find in the exercise no 3.3

Samacheer Kalvi Math Solution for Exercise 3.3 part 4

(iii) 0,4

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = 0    β = 4

          x² - (0 + 4) x + 0 (4) = 0

          x² - 4 x = 0          


(iv) 2,1/5

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = √2    β = 1/5

          x² - (√2 + (1/5)) x + √2 (1/5) = 0

          x² - (5√2 + 1)/5 x + (√2/5) = 0

In the page samacheer kalvi math solution for exercise 3.3 part 4 we are going to see the solution of next problem


(v) 1/3,1

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = 1/3    β = 1

          x² - ((1/3) + 1) x + (1/3) (1) = 0

          x² - [(1 + 3)/3] x + (1/3) = 0

          x² - (4/3) x + (1/3) = 0

          3x² - 4 x + 1 = 0         


(vi) 1/2, -4

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = 1/2    β = -4

          x² - ((1/2) + (-4)) x + (1/2) (-4) = 0

          x² - [(1 - 8)/2] x + (1/3) = 0

          x² - (4/3) x + (1/3) = 0

          3x² - 4 x + 1 = 0   


(vii) 1/3,1/3

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = 1/3    β = 1/3

          x² - ((1/3) + (1/3)) x + (1/3) (1/3) = 0

          x² - [(1 + 1)/3] x + (1/9) = 0

          x² - (2/3) x + (1/9) = 0

          9x² - 6 x + 1 = 0 


(viii) √3 , 2

Solution:

General form of quadratic equation with roots α and β is

x² - (α + β) x + αβ = 0

         α = √3   β = 2

          x² - (√3 + 2) x + (√3) 2 = 0

          x² - (2 + √3) x + 2√3 = 0




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