EQUATION OF THE LINE WORKSHEET WITH ANSWER

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(1)  Find the slope of the following straight lines

(i) 5y āˆ’3 = 0           Solution

(ii) 7 x - (3/17)  = 0          Solution

(2)  Find the slope of the line which is

(i) parallel to y = 0.7x āˆ’11          Solution

(ii)  perpendicular to the line x = āˆ’11          Solution

(3)  Check whether the given lines are parallel or perpendicular

(i)  (x/3) + (y/4) + (1/7) = 0 and (2x/3) + (y/2) + (1/10) = 0

Solution

(ii) 5x + 23y + 14 = 0 and 23x āˆ’ 5y + 9 = 0

Solution

(4)  If the straight lines 12y = āˆ’(p + 3)x +12 , 12x āˆ’7y = 16 are perpendicular then find ā€˜p’.     Solution 

Answer Key

1)  the slope of the given line is 0.

2)  the slope of the given line is undefined.

3) i)  y = 0.7x - 11    ii)  0

4)  Parallel

5)  perpendicular

6)  p = 4

Problem 1 :

A(-3, 0) B(10, -2) and C(12, 3) are the vertices of Ī”ABC. Find the equations of the altitudes through A, B and C in general form

Solution

Problem 2 :

Write the equation of the perpendicular bisector that goes through the line segment with end points of (9, 5) and (-7, 13).

Solution

Problem 3 :

Write the equation of the perpendicular bisector that goes through the line segment with end points of (10, -10) and B (2, 2).

Solution

Problem 4 :

Write the equation of the perpendicular bisector that goes through the line segment with end points of (-10, -8) and B (-14 , 8).

Solution

Answer Key

1)  Equation of the altitude AD : 2x + 5y + 6 = 0, 

Equation of the altitude BE : 5x + y - 48 = 0

Equation of the altitude CF :  13x - 2y - 150 = 0

2)  y = 2x + 7

3)  2x - 3y = 0

4)  y = (-3/2)x + 18

Problem 1 :

Find the equation of perpendicular bisector of the line joining the points A(-4, 2) and B(6, -4) in general form.

Solution

Problem 2 :

Write an equation of the line in y = mx + b form that is the perpendicular bisector of the line segment having endpoints of (1, 2) and (2, 4)

Solution

Problem 3 :

The straight line p has the equation 3x āˆ’ 4y + 8 = 0. The straight line q is parallel to p and passes through the point with coordinates (8, 5).

a Find the equation of q in the form y = mx + c. The straight line r is perpendicular to p and passes through the point with coordinates (āˆ’4, 6).

b Find the equation of r in the form ax + by + c = 0, where a, b and c are integers.

c Find the coordinates of the point where lines q and r intersect.

Solution

Answer Key

1)  5x - 3y - 8 = 0

2)  y = (-1/2)x + (15/4)

3)  a)  3x - 4y = 4   b)  4x + 3y = 2

c)  the point of intersection is (4/5, -2/5)

Question 1 :

Find the equation of a straight line through the intersection of lines 7x + 3y = 10, 5x āˆ’ 4y = 1 and parallel to the line 13x + 5y +12 = 0

Solution

Question 2 :

Find the equation of a straight line through the intersection of lines 5x āˆ’6y = 2, 3x + 2y = 10 and perpendicular to the line 4x āˆ’7y +13 = 0

Solution

Answer Key

1) 13x + 5y - 18  =  0

2)  49x + 28y - 156  =  0

Question 1 :

Find the equation of a straight line joining the point of intersection of 3x + y + 2 = 0 and x āˆ’ 2y āˆ’ 4 = 0 to the point of intersection of 7x āˆ’ 3y = āˆ’12 and 2y = x + 3

Solution

Question 2 :

Find the equation of a straight line through the point of intersection of the lines 8x + 3y = 18, 4x + 5y = 9 and bisecting the line segment joining the points (5, –4) and (–7, 6).

Solution

Answer Key

1)  31x + 15y + 30  =  0

2)  4x + 13y - 9  =  0

Problem 1 :

Write the equation of the lines through the point (1, -1)

(i) parallel to x + 3y - 4 = 0

(ii) perpendicular to 3x + 4y = 6

Solution

Problem 2 :

If (āˆ’4, 7) is one vertex of a rhombus and if the equation of one diagonal is 5x āˆ’ y + 7 = 0, then find the equation of another diagonal.

Solution

Problem 3 :

The line with equation 2x āˆ’ 3y + 5 = 0 is perpendicular to the line with equation 3x + ky āˆ’ 1 = 0. Find the value of the constant k.

Solution

Problem 4 :

The straight line l1 passes through the points with coordinates (āˆ’3, 7) and (1, āˆ’5).

a) Find an equation of the line l1 in the form ax + by + c = 0, where a, b and c are integers. The line l2 is perpendicular to l1 and passes through the point with coordinates (4, 6).

b) Find, in the form k√5, the distance from the origin of the point where l1 and l2 intersect.

Solution

Problem 5 :

If AB is defined by the endpoints A(4, 2) and B(8, 6), write an equation of the line that is the perpendicular bisector of AB.

Answer Key

1)  i) x + 3y - 4 = 0   ii)   4x - 3y - 1 = 0

2)  x + 5y - 31 = 0

3)  the value of k is 2.

4)  the value of k is 5

5)  y = -x + 10

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