(1) Find the slope of the following straight lines
(i) 5y −3 = 0 Solution
(ii) 7 x - (3/17) = 0 Solution
(2) Find the slope of the line which is
(i) parallel to y = 0.7x −11 Solution
(ii) perpendicular to the line x = −11 Solution
(3) Check whether the given lines are parallel or perpendicular
(i) (x/3) + (y/4) + (1/7) = 0 and (2x/3) + (y/2) + (1/10) = 0
(ii) 5x + 23y + 14 = 0 and 23x − 5y + 9 = 0
(4) If the straight lines 12y = −(p + 3)x +12 , 12x −7y = 16 are perpendicular then find ‘p’. Solution
1) the slope of the given line is 0.
2) the slope of the given line is undefined.
3) i) y = 0.7x - 11 ii) 0
4) Parallel
5) perpendicular
6) p = 4
Problem 1 :
A(-3, 0) B(10, -2) and C(12, 3) are the vertices of ΔABC. Find the equations of the altitudes through A, B and C in general form
Problem 2 :
Write the equation of the perpendicular bisector that goes through the line segment with end points of (9, 5) and (-7, 13).
Problem 3 :
Write the equation of the perpendicular bisector that goes through the line segment with end points of (10, -10) and B (2, 2).
Problem 4 :
Write the equation of the perpendicular bisector that goes through the line segment with end points of (-10, -8) and B (-14 , 8).
1) Equation of the altitude AD : 2x + 5y + 6 = 0,
Equation of the altitude BE : 5x + y - 48 = 0
Equation of the altitude CF : 13x - 2y - 150 = 0
2) y = 2x + 7
3) 2x - 3y = 0
4) y = (-3/2)x + 18
Problem 1 :
Find the equation of perpendicular bisector of the line joining the points A(-4, 2) and B(6, -4) in general form.
Problem 2 :
Write an equation of the line in y = mx + b form that is the perpendicular bisector of the line segment having endpoints of (1, 2) and (2, 4)
Problem 3 :
The straight line p has the equation 3x − 4y + 8 = 0. The straight line q is parallel to p and passes through the point with coordinates (8, 5).
a Find the equation of q in the form y = mx + c. The straight line r is perpendicular to p and passes through the point with coordinates (−4, 6).
b Find the equation of r in the form ax + by + c = 0, where a, b and c are integers.
c Find the coordinates of the point where lines q and r intersect.
1) 5x - 3y - 8 = 0
2) y = (-1/2)x + (15/4)
3) a) 3x - 4y = 4 b) 4x + 3y = 2
c) the point of intersection is (4/5, -2/5)
Question 1 :
Find the equation of a straight line through the intersection of lines 7x + 3y = 10, 5x − 4y = 1 and parallel to the line 13x + 5y +12 = 0
Question 2 :
Find the equation of a straight line through the intersection of lines 5x −6y = 2, 3x + 2y = 10 and perpendicular to the line 4x −7y +13 = 0
1) 13x + 5y - 18 = 0
2) 49x + 28y - 156 = 0
Question 1 :
Find the equation of a straight line joining the point of intersection of 3x + y + 2 = 0 and x − 2y − 4 = 0 to the point of intersection of 7x − 3y = −12 and 2y = x + 3
Question 2 :
Find the equation of a straight line through the point of intersection of the lines 8x + 3y = 18, 4x + 5y = 9 and bisecting the line segment joining the points (5, –4) and (–7, 6).
1) 31x + 15y + 30 = 0
2) 4x + 13y - 9 = 0
Problem 1 :
Write the equation of the lines through the point (1, -1)
(i) parallel to x + 3y - 4 = 0
(ii) perpendicular to 3x + 4y = 6
Problem 2 :
If (−4, 7) is one vertex of a rhombus and if the equation of one diagonal is 5x − y + 7 = 0, then find the equation of another diagonal.
Problem 3 :
The line with equation 2x − 3y + 5 = 0 is perpendicular to the line with equation 3x + ky − 1 = 0. Find the value of the constant k.
Problem 4 :
The straight line l1 passes through the points with coordinates (−3, 7) and (1, −5).
a) Find an equation of the line l1 in the form ax + by + c = 0, where a, b and c are integers. The line l2 is perpendicular to l1 and passes through the point with coordinates (4, 6).
b) Find, in the form k√5, the distance from the origin of the point where l1 and l2 intersect.
Problem 5 :
If AB is defined by the endpoints A(4, 2) and B(8, 6), write an equation of the line that is the perpendicular bisector of AB.
1) i) x + 3y - 4 = 0 ii) 4x - 3y - 1 = 0
2) x + 5y - 31 = 0
3) the value of k is 2.
4) the value of k is 5
5) y = -x + 10
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