# HOW TO FIND THE SLOPE FROM AN EQUATION

How to Find the Slope From an Equation ?

Here we are going to see, some example problems to find slope of the line from the given equation.

## How to Find the Slope From an Equation - Questions

Question 1 :

Find the slope of the following straight lines

(i) 5y −3 = 0

Solution :

Slope (m)  =  -coefficient of x/coefficient of y

=  0/5

m  =  0

Hence the slope of the given line is 0.

(ii) 7 x - (3/17)  = 0

Solution :

Slope (m)  =  -coefficient of x/coefficient of y

=  7/0

m  = undefined

Hence the slope of the given line is undefined.

Question 2 :

Find the slope of the line which is

(i) parallel to y = 0.7x −11

Solution :

If two lines are parallel, then the slopes will be equal.

Slope of the given line :

m = 0.7

Slope of the line parallel to the given line is 0.7

(ii)  perpendicular to the line x = −11

Solution :

x + 11  =  0

Slope of the given line  =  -1/0

=  undefined.

Slope of the line perpendicular to the given line

=  -1/undefined

=  0

## How to Check If the Given Lines are Perpendicular

Question 3 :

Check whether the given lines are parallel or perpendicular

(i)  (x/3)+(y/4)+(1/7) = 0 and (2x/3)+(y/2)+(1/10) = 0

Solution :

Let us find the slopes of the given lines.

m = -coefficient of x/coefficient of y

Slope of the 1st line :

=  (-1/3)/(1/4)

m1  =  -4/3

Slope of the 2nd line :

=  (-2/3)/(1/2)

m2  =  -4/3

Since the slopes are equal, the given lines are parallel.

(ii) 5x + 23y + 14 = 0 and 23x − 5y + 9 = 0

Solution :

Let us find the slopes of the given lines.

m = -coefficient of x/coefficient of y

Slope of the 1st line :

m1  =  -5/23

Slope of the 2nd line :

=  23/(-5)

m2  =  -23/5

m1 (m2)  =  -1

Hence the given lines are perpendicular.

Question 4 :

If the straight lines 12y = −(p + 3)x +12 , 12x −7y = 16 are perpendicular then find ‘p’.

Solution :

If two lines are perpendicular, then product of their slopes = -1

Slope of the 1st line :

12y = −(p + 3)x +12

By dividing the entire equation by 12, we get

y =  [−(p + 3)/12]x + (12/12)

y =  [−(p + 3)/12]x + 1

m1  =  -(p + 3)/12

Slope of the 2nd line :

12x −7y = 16

m = -12/(-7)

m2  =  12/7

m⋅ m2  =  -1

( -(p + 3)/12) (12/7)  =  -1

-(p + 3)/7  =  -1

p + 3  =  7

p  =  7 - 3

p  =  4 After having gone through the stuff given above, we hope that the students would have understood, "How to Find the Slope From an Equation".

Apart from the stuff given in this section "How to Find the Slope From an Equation"if you need any other stuff in math, please use our google custom search here.