DIGITAL SAT MATH PROBLEMS AND SOLUTIONS
(Part - 41)

Problem 1 :

The point (a, a) satisfies the linear inequality y ≤ mx + 1, and a is greater than 0. The value of m must greater than or equal to what value?

Solution :

Problem 2 :

From 2015 to 2016 the population of a town grew by 25%. From 2016 to 2017 the population grew by 16%. If population in 2017 was x, and the population in 2015 was kx, what is the value of k to the nearest hundredth?

Solution :

Problem 3 :

f(x) = -x3 + bx2 + cx + d

The function passes through the points

(12, 0), (-12, 0), (0, 2088) and (p, 0),

where p < -12. What is the value of b + c + d?

Solution :

Problem 4 :

-19(6x - 4)2 + 6(6x - 3)2

The given expression can be written as

where a, b and c are constants. What is the value of

a + b + c?

Solution :

Problem 5 :

In the xy-plane, the line with equation ax – by = 5, where a and b are constants, is perpendicular to the line with equation 11x – 4y = 5. Which of the following equations represents a line that is perpendicular to the line with equation 11x + 12y = 5?

A)  ax – 3by = 5

B)  ax + 3by = 5

C)  3ax – by = 5

D)  3ax + by = 5

Solution :

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