Question 1 :
A circle with center (-7, -4) has a radius equal to 14. The equation x2 + y2 + ax + by + c = 0 represents the circle. What is the value of c?
Answer :
Question 2 :
If k = l + m, which of the following is equivalent to the expression x2 - l2 - 2lm - m2?
A) (x + k)2
B) (x - k)2
C) (x - k)(x + k)
D) x2 - kx - k2
Answer :
Question 3 :
ax2 + 148x + c
In the given expression, a and c are positive constants. If jx + k is a factor of the expression, where j and k are positive constants, what is the greatest possible value of ac?
Answer :
Question 4 :
Lines c and d are perpendicular. If the equation of line c is y = mx + b and the lines intersect at point (7, 6). Which point lies on line d?
A) (7 + m, 7)
B) (2m, 8)
C) (7 + 2m, 4)
D) (7 - 3m, 3)
Answer :
Question 5 :
What is the value of k, if the given equation only has one solution?
¼|x - 4| - 30 = 2k
Answer :
Question 6 :
In the given pair of equations a and b are constants. The graph of this pair of equations in the xy-plane is a pair of perpendicular lines. Which of the following pairs of equations also represents a pair of perpendicular lines?
13x + 17y = 10
ax + by = 10
A) 39x + 17y = 10
ax – 3by = 10
B) 13x - 17y = 10
ax + by = 10
C) 65x + 17y = 10
5ax + by = 10
D) 52x + 34y = 10
2ax + 4by = 10
Answer :
Question 7 :
Which equation correctly gives c in terms of d, e and f?
73/c = 73/d + 73/e + 73/f
A) c = d + e + f
B) c = def/(d + e + f)
C) c = (d + e + f)/def
D) c = def/(de + df + ef)
Answer :
Question 8 :
For the exponential function f, the value of f(3) is k, where k is a constant. Which of the following equivalent forms of the function f shows the value of k as the coefficient or the base?
A) f(x) = 3(4)(4)x + 1)
B) f(x) = 3,072(4)(4)x - 4
C) f(x) = 12(4)(4)x
D) f(x) = 768(4)(4)x - 3
Answer :
Question 9 :
6√12/(3 - √5) can be written in the form √x + √y, where x and y are positive integers. What is the value of x + y?
Answer :
Question 10 :
A rocket’s speed is increasing at a rate of 14.6 meters per second squared. What is the rate in miles per minute squared? (1 mile = 1,609 meters)
Answer :
10 Hard Digital SAT Math Questions (Part - 1)
10 Hard Digital SAT Math Questions (Part - 2)
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