10 Hard SAT Math Questions (Part - 29)

Question 1 :

A circle with center (-7, -4) has a radius equal to 14. The equation x2 + y2 + ax + by + c = 0 represents the circle. What is the value of c?

Answer :

Question 2 :

If k = l + m, which of the following is equivalent to the expression x2 - l2 - 2lm - m2?

A)  (x + k)2

B)  (x - k)2

C)  (x - k)(x + k)

D)  x2 - kx - k2

Answer :

Question 3 :

ax2 + 148x + c

In the given expression, a and c are positive constants. If jx + k is a factor of the expression, where j and k are positive constants, what is the greatest possible value of ac?

Answer :

Question 4 :

Lines c and d are perpendicular. If the equation of line c is y = mx + b and the lines intersect at point (7, 6). Which point lies on line d?

A)  (7 + m, 7)

B)  (2m, 8)

C)  (7 + 2m, 4)

D)  (7 - 3m, 3)

Answer :

Question 5 :

What is the value of k, if the given equation only has one solution?

¼|x - 4| - 30 = 2k

Answer :

Question 6 :

In the given pair of equations a and b are constants. The graph of this pair of equations in the xy-plane is a pair of perpendicular lines. Which of the following pairs of equations also represents a pair of perpendicular lines?

13x + 17y = 10

ax + by = 10

A) 39x + 17y = 10

      ax – 3by = 10

B) 13x - 17y = 10

      ax + by = 10

C) 65x + 17y = 10

      5ax + by = 10

D) 52x + 34y = 10

      2ax + 4by = 10

Answer :

Question 7 :

Which equation correctly gives c in terms of d, e and f?

73/c = 73/d + 73/e + 73/f

A)  c = d + e + f

B)  c = def/(d + e + f)

C)  c = (d + e + f)/def

D)  c = def/(de + df + ef)

Answer :

Question 8 :

For the exponential function f, the value of f(3) is k, where k is a constant. Which of the following equivalent forms of the function f shows the value of k as the coefficient or the base?

A)  f(x) = 3(4)(4)x + 1)

B)  f(x) = 3,072(4)(4)x - 4 

C)  f(x) = 12(4)(4)x

D)  f(x) = 768(4)(4)x - 3

Answer :

Question 9 :

6√12/(3 - √5) can be written in the form √x + √y, where x and y are positive integers. What is the value of x + y?

Answer :

Question 10 :

A rocket’s speed is increasing at a rate of 14.6 meters per second squared. What is the rate in miles per minute squared? (1 mile = 1,609 meters)

Answer :

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