10 Hard SAT Math Questions
(Part - 2)

Question 1 :

For the exponential function g, the value of g(3) is q, where q is a constant. Which of the following equivalent forms of the function g shows the value of q as the coefficient or the base?

A)  g(x) = 27(1.2)x + 3

B)  g(x) = 64(1.2)x - 1

C)  g(x) = 172(1.2)x

D)  g(x) = 1036(1.2)x – 3

Answer :

Question 2 :

The positive number a is 520% of the number b, and a is 65% of the number c. If c is p% of b, which of the following is the value of p?

A)  3.38

B)  8

C)  338

D)  800

Answer :

Question 3 :

Let f(x) = 42(a/21)x + b + c.

How many times does the graph of the given function in the xy-plane cross the x-axis, where a, b and c are integer constants such that a > 21, b < 0 and c < b?

A)  Zero

B)  Once

C)  Twice

D)  Three

Answer :

Question 4 :

x2 + 10x + y2 + 12y – 723 = 0

In the xy-plane, the graph of the given equation is a circle. If this circle is inscribed in a square, what is the perimeter of the square?

Answer :

Question 5 :

A right circular cone has a volume of 2592π cubic inches, and the area of its base is 324π square inches. What is the slant height, in inches, of this cone?

Answer :

Question 6 :

The area of a triangle is equal to x2 square inches. The base of the triangle is 21 – x inches, and the height of the triangle is 4 – x inches. Which of the following could be the value of x?

A)  –28

B)  –3

C)  1/2

D)  2

Answer :

Question 7 :

The table gives the volume of two similar cylinders. If the radius of cylinder A is 6 cm, what is the value of rs?

digitalsatmath379.png

volume = πr2h

surface area = 2πr2 + 2πrh

Answer :

Question 8 :

In triangle ABC, angle C is a right angle, point D lies on AB, point E lies on BC, and DE is parallel to AC. If the length of AB is 39 units, DE is 8 units, the length of AC is greater than the length of BC, and the area of the triangle ABC is 270 square units, what is the length of BE, in units?

Answer :

Question 9 :

If k = + m, which of the following is equivalent to the expression x22 – 2ℓmm2?

A)  (x + k)2

B)  (xk)2

C)  (x + k)(xk)

D)  x2kxk2

Answer :

Question 10 :

In the equation below, k is a constant. What is the value of k, if the equation has one solution?

¼|x – 4| – 30 = 2k

Answer :

You might like these

10 Hard Digital SAT Math Problems (Part - 1)

10 Hard Digital SAT Math Problems (Part - 2)

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