PRACTICE PROBLEMS ON CYCLIC QUADRILATERAL WITH ANSWERS

Find the missing angles in the following problems given below.

Problem 1 :

Find x given : 

Solution

Problem 2 :

Solution

Problem 3 :

Solution

Problem 4 :

Solution

Problem 5 :

Solution

Problem 6 :

Solution

Problem 7 :

Solution

Problem 8 :

Find the value of x in the given figure. 

Solution

Problem 9 :

In the given figure, AC is the diameter of the circle with center O. If <ADE = 30° ; <DAC = 35° and <CAB = 40°. Find (i) <ACD   (ii)  <ACB  (iii)  <DAE

Solution

Problem 10 :

Find all the angles of the given cyclic quadrilateral ABCD in the figure.

Solution

Problem 11 :

In the given figure, ABCD is a cyclic quadrilateral where diagonals intersect at P such that <DBC = 40° and <BAC = 60° find

(i)  <CAD   (ii)  BCD

Solution

Problem 12 :

In the figure given below, PQ is a diameter of a circle with centre O. If <PQR = 55°, <SPR = 25° and <PQM = 50°.

Find

(i)  <QPR

(ii)  <QPM and

(iii) <PRS

Solution

Problem 13 :

In the figure at right, ABCD is a cyclic quadrilateral whose diagonals intersect at P such that <DBC = 30° and <BAC = 50° . Find

(i) <BCD

(ii) <CAD

Solution

Problem 14 :

In the figure given below, O is the centre of a circle and <ADC = 120°. Find the value of x.

Solution

Problem 15 :

In the figure given below, ABCD is a cyclic quadrilateral in which AB || DC. If <BAD  =  100° find

(i) <BCD

(ii) <ADC

(iii) <ABC

Solution

Problem 16 :

In the figure given below, ABCD is a cyclic quadrilateral in which <BCD = 100° and <ABD = 50° find <ADB

Solution

Answers :

(1)  x  =  93

(2)  x  =  107

(3)  x  =  70

(4)  x  =  90

(5)  x  =  62

(6)  a = 80

(7)   a  =  63

(8)  x  =  30

(9)  (i)  <ACD  =  55  (ii)  <ACB  =  50  (iii)  <EDA  =  25

(10)  x = 14, y = 30, <A = 64, <B = 80, <C = 116, <D = 100

(11)  <DAC  =  40, <BCD  =  80°

(12)  (i)  <QPR  =  35°, (ii)  <QPM  =  40°,  (iii)  <PRS  =  30

(13)  (i)  <DCB  =  100°  (ii)  <CAD  =  30°

(14)   x = 30°

(15)  (i)  <BCD  =  80°  (ii)  <ADC  =  80°  (iii)  <ABC  =  100°

(16)  <ABD  =  50°

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