LOGARITHM PROBLEMS AND SOLUTIONS
(Part - 3)

Problem 1 :

If a = log₂₄ 12, b = log₃₆ 24 and c = log₄₈ 36, then 1 + abc is equal to

A)  2

B)  2ab

C)  2ac

D)  2bc

Solution :

Problem 2 :

A)  3log₁₀ 2

B)  3log₁₀ 2

C)  3log₁₀ 2

D)  3log₁₀ 2

Solution :

Problem 3 :

A)  12

B)  14

C)  16

D)  8

Solution :

Problem 4 :

If log (m + n) = log m + log n, m can be expressed as

Solution :

Problem 5 :

Solve for x :

log₄ (x² + x) - 2log₁₆ (x + 1) = 2

Solution :

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