SOLVING LOGARITHMIC EQUATIONS WORKSHEET

Problem 1 : 

Solve  for x :

Problem 2 : 

Solve for y :

Problem 3 :

Solve for z :

logz8√2 = 7

Problem 4 : 

Solve for k :

-3 = logk0.001

Problem 5 :

Solve for x :

log5[5log3(x)] = 2

Problem 6 :

Solve for m :

m + 2log27(9) = 0

Problem 7 :

If 2log(y) = 4log(3),  then find the value of y

Problem 8 :

If 3p is equal to log(0.3) to the base 9, then find the value of p.

Problem 9 :

Solve for r :

Problem 10 :

Solve for q :

Problem 11 :

Solve for v :

log4(v + 4) + log48 = 2

Problem 12 :

Solve for w :

log6(w + 4) - log6(w - 1) = 1

Problem 13 :

Solve for g :

Problem 14 :

Solve for x :

81= log2(512)

Answers

1. Answer :

Convert it to exponential form.

2. Answer :

Convert it to exponential form.

3. Answer :

logz8√2 = 7

Convert it to exponential form. 

125√5 = z7

 2 ⋅ 2 ⋅ 2 ⋅ √2 = x7

Each 2 can be expressed as (√2 ⋅ √2).

Then,

√2 ⋅ √2 ⋅ √2 ⋅ √2 ⋅ √2 ⋅ √2 ⋅ √2 = x7

√2= x7

Because the exponents are equal, bases can be equated. 

x = √2

4. Answer :

-3 = logk0.001

Convert it to exponential form. 

k-3 = 0.001

Take reciprocal on both sides. 

k= 1000 

k3 = 103

Because the exponents are equal, bases can be equated. 

k = 10

5. Answer :

log5[5log3(x)] = 2

Convert it to exponential form. 

5log3(x) = 52

5log3(x) = 25

Divide both sides by 5.

log3(x) = 5

Convert it to exponential form. 

x = 35

x = 243

6. Answer :

m + 2log27(9) = 0

m = -2log27(9)

x = log27(9-2)

Convert it to exponential form. 

27x = 9-2

(33)= (32)-2

33x = 3-4

Because the bases are equal, exponents can be equated. 

3x = -4

7. Answer :

2log(y) = 4log(3)

Divide each side by 2.

log(y) = 2log(3)

log(y) = log(32)

log(y) = log(9)

y = 9

8. Answer :

From the information given, we have

3p = log9(0.3)

Solve for p.

9. Answer :

7r - 4 = 5(r + 2)

7r - 4 = 5r + 10

2r - 4 = 10

2r = 14

r = 7

10. Answer :




q = 31

q = 3

11. Answer :

log4(v + 4) + log48 = 2

log4[8(v + 4)] = 2

log4(8v + 32) = 2

8v + 32 = 42

8v + 32 = 16

8v = -16

v = -2

12. Answer :

log6(w + 4) - log6(w - 1) = 1

w + 4 = 6(w - 1)

w + 4 = 6w - 6

-5w + 4 = -6

-5w = -10

w = 2

13. Answer :




log2(g) = 1

g = 21

g = 2

14. Answer :

81= log2(512)

81= log2(29)

81= 9log2(2)

(92)= 9(1)

92x = 91

2√x = 1

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