HONORS ALGEBRA 2 PROBLEMS WITH SOLUTIONS
(Part - 4)

Problem 1 :

Solve for x :

Solution :

Problem 2 :

Solve for x :

Solution :

Problem 3 :

A number consists of two digits, the digit in the tens place is twice the digit in the ones place. If 18 be subtracted from the number, the digits are reversed. Find the number.

Solution :

Problem 4 :

Find the value of k from (√9)-7 x (√3)-5 = 3k.

Solution :

Problem 5 :

Solve for x :

4x - 3 ⋅ 2x + 2 + 25 = 0

Solution :

You might like these

Honors Algebra 2 Problems with Solutions (Part - 1)

Honors Algebra 2 Problems with Solutions (Part - 2)

Honors Algebra 2 Problems with Solutions (Part - 3)

Honors Algebra 2 Problems with Solutions (Part - 4)

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

©All rights reserved. onlinemath4all.com

Recent Articles

  1. 10 Hard SAT Math Questions (Part - 16)

    Sep 18, 25 11:19 AM

    digitalsatmath362.png
    10 Hard SAT Math Questions (Part - 16)

    Read More

  2. 10 Hard SAT Math Questions (Part - 15)

    Sep 18, 25 10:07 AM

    10 Hard SAT Math Questions (Part - 15)

    Read More

  3. 10 Hard SAT Math Questions (Part - 14)

    Sep 17, 25 09:38 AM

    digitalsatmath383.png
    10 Hard SAT Math Questions (Part - 14)

    Read More