Formulas are being used in many applications of mathematics.
For example, we use the formula A = πr2 to find area of a circle. It is often helpful to transform such a formula to express a particular variable in terms of the other variables.
Example 1 :
A formula for the total piston displacement of an automobile engine is
P = 0.7854d2sn
where d is the diameter of each cylinder, s is the length of the stroke, and n is the number of cylinders. Solve for the variable s in terms of P, d and n.
Solution :
Write the given formula.
P = 0.7854d2sn
Because we are solving for s, we have to get s alone on one side.
So, divide each side by 0.7854d2n.
P / 0.7854d2n = s
Note :
Note that the formula obtained for s in the above example is valid only if d ≠ 0 and n ≠ 0. (Of course, neither n nor d will be zero, since the engine must have cylinders and each cylinder must have a diameter).
Example 2 :
Solve the formula for the variable r :
A = s2 + 2rs
Solution :
Write the given formula.
A = s2 + 2rs
Because we are solving for r, we have to get r alone on one side.
Subtract s2 from each side.
A - s2 = 2rs
Divide each side by 2s.
(A - s2) / 2s = r
Note :
Note that the formula obtained for s in the above example is valid only if s ≠ 0. And also, if s is the length of a side, then s > 0.
Example 3 :
Solve the equation for the variable x :
c = ax - b
Solution :
Write the given equation.
c = ax - b
Because we are solving for x, we have to get x alone on one side.
Add b to each side.
b + c = ax
Divide each side by a.
(b + c) / a = x
Example 4 :
Solve the equation for the variable x :
C = mv2 / r
Solution :
Write the given equation.
C = mv2 / r
Because we are solving for r, we have to get r alone on one side.
Take reciprocal on each side.
1 / C = r / mv2
Multiply each side by mv2.
mv2 ⋅ (1 / C) = (r / mv2) ⋅ mv2
mv2 / C = r
Example 5 :
Solve the given formula for the variable h. State the restrictions, if any, for the formula obtained to be meaningful.
A = 1/2 ⋅ h ⋅ (a + b)
Solution :
Write the given formula.
A = 1/2 ⋅ h ⋅ (a + b)
Because we are solving for h, we have to get h alone on one side.
Multiply each side by 2.
2A = [1/2 ⋅ h ⋅ (a + b)] ⋅ 2
2A = h ⋅ (a + b)
Divide each side by (a + b).
2A / (a + b) = h
Note that the formula obtained for h in the above example is valid only if (a + b) ≠ 0. (If a and b are the lengths of the sides, then a, b > 0 and (a + b) > 0).
Example 6 :
Solve the given formula for the variable F. State the restrictions, if any, for the formula obtained to be meaningful.
C = 5/9 ⋅ (F - 32)
Solution :
Write the given formula.
C = 5/9 ⋅ (F - 32)
Because we are solving for F, we have to get F alone on one side.
Multiply each side by 9/5.
9/5 ⋅ C = [5/9 ⋅ (F - 32)] ⋅ 9/5
9C/5 = F - 32
Add 32 to each side.
9C/5 + 32 = F
Example 7 :
Solve the given formula for the variable y. State the restrictions, if any, for the formula obtained to be meaningful.
m = (x + y + z) / 3
Solution :
Write the given formula.
m = (x + y + z) / 3
Because we are solving for y, we have to get y alone on one side.
Multiply each side by 3.
3m = [(x+ y + z) / 3] ⋅ 3
3m = x + y + z
Subtract x and z from each side.
3m - x - z = y
Example 8 :
Solve the given formula for the variable n. State the restrictions, if any, for the formula obtained to be meaningful.
a = 180(n - 2) / n
Solution :
Write the given formula.
a = 180(n - 2) / n
Because we are solving for n, we have to get n alone on one side.
Multiply each side by n.
na = [180(n - 2) / n] ⋅ n
na = 180(n - 2)
na = 180n - 360
Add 360 to each side.
na + 360 = 180n
Subtract na from each side.
360 = 180n - na
360 = (180 - a)n
Divide each side by (180 - a).
360 / (180 - a) = n
Note that the formula obtained for n in the above example is valid only if (180 - a) ≠ 0, that is a ≠ 180. And also, if n is the number of sides, then n > 0. Then we have (180 - a) > 0, that is a < 180.
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