**Solving problems with unit rates :**

We can solve many real world problems with unit rates.

For example,

If the cost of 7 shirts is $210, then find the cost of 10 shirts.

We can solve the above problem with unit rate.

Here, first we find the unit rate (cost of 1 shirt).

Then we can find the cost of 10 shirts.

Cost of 1 shirt = 210 / 7 = $30.

Cost of 10 shirts = 10 x $30 = $300

**Examples 1 :**

At a summer camp, the campers are divided into groups. Each group has 16 campers and 2 cabins. How many cabins are needed for 112 campers ?

**Solution : **

First we have to find how many campers can accommodate in one cabin.

To find the number of campers accommodated in 1 cabin, we have to divide 16 by 2.

16/2 = 8

8 campers can accommodate in 1 cabin.

To find the number of cabins required for 112 campers, we have to divide 112 by 8.

112 / 8 = 14

Hence, 14 cabins needed for 112 campers.

**Examples 2 :**

If 350 miles of distance covered 7 hours, find the distance covered by 6 hours ?

**Solution : **

First we have to find how many miles of distance covered in 1 hour.

To find the distance covered in 1 hour, we have to divide 350 by 7.

350/7 = 50

In 1 hours, 50 miles of distance covered.

In 6 hours, the distance covered = 6 x 50 = 300 miles.

**Examples 3 :**

Petra jogs 3 miles in 27 minutes. Find the unit rate in minutes per mile. How long would it take her to jog 5 miles ?

**Solution : **

To find the unit rate in minutes per mile, we have to divide 27 minutes by 3 miles.

27 ÷ 3 = 27/3 = 9

Unit rate in minutes per mile = 9

That is, it takes 9 minutes to cover 1 mile of distance.

To find the time taken to cover 5 miles, we have to multiply 5 and 9

5 x 9 = 45

Therefore, it will take 45 minutes to cover 5 miles of distance.

After having gone through the stuff given above, we hope that the students would have understood "How to solve problems with unit rates".

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