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Question 1 :
The area of a rectangular sandbox is 56 2/3 square feet. The length of the sandbox is 8 1/2 feet. What is the width ?
Answer :
We know the formula to find area of the rectangle.
That is,
Area of the rectangle = length x width
Plug the known values area and length and solve for the unknown value width.
56 2/3 = 8 1/2 x width
170/3 = 17/2 x width
(170/3) x (2/17) = width
20/3 = width
6 2/3 = width
Therefore, the width of the rectangle is 6 2/3 feet.
Question 2 :
Mr. Webster is buying carpet for an exercise room where the basement of the room is in the shape of rectangle. The length and width of the room are 18 2/5 feet and 12 1/2 feet respectively. Find the total cost of the carpet, if the price of the carpet is $3 per square feet ?
Solution :
To know the total cost of the carpet, first we have to know the area of the basement.
Area of the basement = length x width
= 18 2/5 x 12 1/2
= (92/5) x (25/2)
= 46 x 5
= 230 square feet
So, we need 230 square feet of carpet.
The cost each square feet of carpet = $3
Then, the cost of 230 square ft of carpet is
= 3 x 230
= $690
Therefore, the total cost of the carpet is $690.
Question 3 :
David is cooking enough lentils for lentil barley soup and lentil salad. The lentil barley soup recipe calls for 3/4 cup of dried lentils. The lentil salad recipe calls for 1 1/2 cups of dried lentils. David has a 1/8 -cup scoop. How many scoops of dried lentils will David need to have enough for the soup and the salad ?
Solution :
David needs 3/4 cup of dried lentils for soup and 1 1/2 cups for salad.
Total amount dried lentils that David need is
= (3/4) + (1 1/2)
= 3/4 + 3/2
= 3/4 + 6/4
= (3+6) / 4
= 9/4
David needs 9/4 cups of dried lentils for both the soup and the salad.
To find how many 1/8 -cup scoops he needs, divide the total amount of dried lentils into groups of 1/8.
Then, we have
= 9/4 ÷ 1/8
= 9/4 x 8/1
= 9 x 2
= 18
So, David will need 18 scoops of dried lentils to have enough for both the lentil barley soup and the lentil salad.
Question 4 :
If the numerator of a fraction is increased by 2 and the denominator by 1, it becomes 1. In case, the numerator is decreased by 4 and the denominator by 2, it becomes 1/2. Find the fraction.
Solution :
Let "x/y" be the required fraction.
"If the numerator is increased by 2 and the denominator by 1, the fraction becomes 1"
From the above information, we have
(x + 2) / (y + 1) = 1
Simplify.
x + 2 = y + 1
x-y = -1 ---(1)
"In case the numerator is decreased by 4 and the denominator by 2, the fraction becomes 1/2"
From the above information, we have
(x - 4) / (y - 2) = 1/2
Simplify.
(x - 4) / (y - 2) = 1/2
2(x - 4) = y - 2
2x-y = 6---(1)
Solving (1) and (2), we get
x = 7
y = 8
Then,
x/y = 7/8
So, the required fraction is 7/8.
Question 5 :
The ratio of number of boys and number of girls in a school is found to be 15 : 32. How many boys and equal number of girls should be added to bring the ratio to 2/3 ?
Solution :
Ratio between boys to girls = 15 : 32
Let x be the number of boys and girls.
(15 + x) : (32 + x) = 2/3
(15 + x) / (32 + x) = 2/3
3(15 + x) = 2(32 + x)
45 + 3x = 64 + 2x
3x - 2x = 64 - 45
x = 19
So, the required number of boys and girls is 19. Option a is correct.
Question 6 :
The sum of a rational number and its reciprocal is 13/6. Find the number.
Solution :
Let x be the number and 1/x is its reciprocal.
x + 1/x = 13/6
(x2 + 1)/x = 13/6
6(x2 + 1) = 13x
6x2 + 6 = 13x
6x2 - 13x + 6 = 0
(3x - 2)(2x - 3) = 0
x = 2/3 and x = 3/2
So, the required number is 2/3 or 3/2.
Question 7 :
The sum of two numbers is 184. If one third of the one exceeds one seventh of the other by 8, find the smaller number.
Solution :
Let x be one number, then the other number be 184 - x.
1/3 of x = 1/7 of (184 - x) + 8
x/3 = [(184 - x)/7] + 8
x/3 - [(184 - x)/7] = 8
[7x - 3(184 - x)]/21 = 8
7x - 552 + 3x = 8(21)
10x - 552 = 168
10x = 168 + 552
10x = 720
x = 720/10
x = 72
184 - x ==> 184 - 72 ==> 112
So, the smaller number is 72.
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