LINEAR EQUATIONS WITH ONE UNKNOWN

Definition of a Linear Equation :

A linear equation in one variable is an equation that has one unknown.

It can be written in the form,

ax + b  =  0

(where a and b are real numbers and a ≠ 0)

To solve linear equations with one unknown, we have to be aware of inverse operations.

  • Inverse operation for addition is subtraction.
  • Inverse operation for subtraction is addition.
  • Inverse operation for multiplication is division.
  • Inverse operation for division is multiplication.

Problem 1 :

9c + 1 = 10

Solution  :

Given , 9c + 1 = 10

9c + 1 – 1 = 10 - 1

9c =  10 – 1

9c  =  9

c  =  9/9

c  =  1

Problem 2 :

6y – 5  =  7

Solution :

Given , 6y – 5  =  7

6y – 5 + 5 =  7 + 5

6y  =  7 + 5

6y  =  12

y  =  12/6

y   =  2

Problem 3 :

8  =  3a – 4

Solution :

Given , 8  =  3a – 4

8 + 4  =  3a – 4 + 4

8 + 4  =  3a

12  =  3a

12/3  =  a

4  =  a

Problem 4 :

m/5 + 9 = 11

Solution :

Given , m/5 + 9 = 11

m/5 + 9 – 9 =  11 - 9 

m/5  =  2

m  =  2 × 5 

m  =  10

Problem 5 :

13 + 7x =  27

Solution :

Given , 13 + 7x =  27

13 + 7x – 13 = 27 – 13

7x  =  27 – 13

7x  =  14

x =  14/7

x  =  2

Problem 6 :

17 – q = 6

Solution :

Given , 17 – q = 6

17 – q – 17 =  6 - 17

-q  =  -11

q  =  11 

Problem 7:

(n – 31)/4 =  2

Solution :

 Given , (n – 31)/4 =  2

n – 31  =  8

n  =  8 + 31

n  =  39 

Problem 8:

1 + 2r  =   35

Solution :

Given , 1 + 2r =   35

1 + 2r – 1  = 35 - 1

2r  =  35 – 1

2r  =  34

r  = 34 /2

r = 17

Problem 9:

42 + 5t =  8t

Solution :

Given , 42 + 5t =  8t

42 + 5t – 42 =  8t - 42

    5t = 8t – 42

5t – 8t = -42

-3t  =  - 42

t = 42/3

t = 14

Problem 10:

4p – 3 =  17

Solution :

Given ,4p – 3 =  17

4p – 3 + 3  =  17 + 3

4p = 17 + 3

4p  =  20

P = 20/4

P = 5

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