GRAPHING POLAR EQUATIONS r EQUAL TO a COS n THETA IN POLAR GRID

Example 1 :

Draw the graph of r  =  4 cos 2θ.

Solution :

a  =  4, n = 2 (even). So the rose curve will have 2n petals.

That is,

2n  =  2(2)  ==>  4 petals

Where will be each petal ?

360 / 4  =  90

Each petal will be apart 90 degree.

The required points are (4, 0) (0, π/2)(-4, π) and (0, 2π).

Example 2 :

Draw the graph of r  =  2 cos 5θ.

Solution :

a  =  2, n = 5 (odd). So the rose curve will have 5 petals.

Where will be each petal ?

360 / 5  =  72

Each petal will be apart 72 degree.

Since it is cosine function, it will lie on the x - axis based on the value of n.

Example 3 :

Draw the graph of r  =  -3 cos 4θ.

Solution :

a  =  3, n = 4 (even). So the rose curve will have 2n petals.

That is,

2n  =  2(4)  ==>  8 petals

Where will be each petal ?

360 / 8  =  45

Each petal will be apart 45 degree.

Since it is cosine function, it will lie on the x - axis based on the value of n.

So the positions of petals are 0, 45, 90, 135, 180, 225, 270, 315, 360.

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