EVALUATING LOGARITHMIC EXPRESSIONS WORKSHEET

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Evaluate each of the following logarithmic expressions :

Problem 1 :

log2 24 - log2 3

Problem 2 :

log3 27 + log3 729

Problem 3 :

log10 8 + log10 5 - log10 4

Problem 4 :

log7 98 - log7 14 + log7 343

Problem 5 :

Problem 6 :

log 50 - (log 25 + log 2)

Problem 7 :

log2 2 + log2 3 - log2 6 - log2 8

Problem 8 :

4log2 2 + log3 27 - 3log2 2 - log2 81

Problem 9 :

log3 2 ⋅ log4 3 ⋅ log5 4 ⋅ log6 5 ⋅ log7 6 ⋅ log8 7

Problem 10 :

log7 21 + log7 77 + log7 88 - log7 121 - log7 24

Problem 11 :

Problem 12 :

5log10 2 + 2log10 3 - 6log64 4

Problem 13 :

Answers

1. Answer :

= log2 24 - log2 3

= log2 8

= log2 23

= 3log2 2

= 3(1)

= 3

2. Answer :

= log3 27 + log3 729

= log3 33 + log3 36

= 3log3 3 + 6log3 3

= 3(1) + 6(1)

= 3 + 6

= 9

3. Answer :

= log10 8 + log10 5 - log10 4

= log10 (8 ⋅ 5) - log10 4

= = log10 40 - log10 4

= log10 10

= 1

4`. Answer :

= log7 98 - log7 14 + log7 343

= log7 7 + log7 73

= 1 + 3log7 7

= 1 + 3(1)

= 1 + 3

= 4

5. Answer :

6. Answer :

= log 50 - (log 25 + log 2)

= log 50 - log (25 ⋅ 2)

= log 50 - log 50

= 0

7. Answer :

= log2 2 + log2 3 - log2 6 - log2 8

= (log2 2 + log2 3) - (log2 6 + log2 8)

= log2 (2 ⋅ 3) - log2 (6 ⋅ 8)

= log2 6 - log2 48

= log2 2-3

= -3log2 2

= -3(1)

= -3

8. Answer :

= 4log2 2 + log3 27 - 3log2 2 - log3 81

= 4(1) + log3 33 - 3(1) - log3 34

= 4 + 3log3 3 - 3 - 4log3 3

= 4 + 3(1) - 3 - 4(1)

= 4 + 3 - 3 - 4

= 0

9. Answer :

= log32 ⋅ log43 ⋅ log54 ⋅ log65 ⋅ log76 ⋅ log87

In the above expression, logarithms have differemnt bases. Group the logarithms with the same base and simplify.

= (log3 2 ⋅ log4 3) ⋅ (log5 4 ⋅ log6 5) ⋅  (log7 6 ⋅ log8 7)

= log4 2 ⋅ log6 4 ⋅ log8 6

= log6 2 ⋅ log8 6

= log8 2

10. Answer :

= log7 21 + log7 77 + log7 88 - log7 121 - log7 24

= log7 (21 ⋅ 77 ⋅ 88) - (log7 121 + log7 24)

= log7 (21 ⋅ 77 ⋅ 88) - log7 (121 ⋅ 24)

= log7 142296 - log7 2904

= log7 49

= log7 72

= 2log7 7

= 2(1)

= 2

11. Answer :

= log8 64

= log8 82

= 2log8 8

= 2(1)

= 2

12. Answer :

= 5log10 2 + 2log10 3 - 6log64 4

= 5log10 2 + 2log10 3 - (2 ⋅ 3)log64 4

= log10 25 + log10 32 - 2log64 43

= log10 32 + log10 9 - 2log64 64

= log10 32 + log10 9 - 2(1)

= log10 32 + log10 9 - 2log10 10

= log10 (32 ⋅ 9) - log10 102

= log10 288 - log10 100

13. Answer :

Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.

About Us  |  Contact Us  |  Privacy Policy

©All rights reserved. onlinemath4all.com

onlinemath4all_official_badge1.png

Recent Articles

  1. Digital SAT Math Practice Test with Answers (Part - 17)

    Sep 29, 26 12:20 PM

    digitalsatmath444.png
    Digital SAT Math Practice Test with Answers (Part - 17)

    Read More

  2. Digital SAT Math Practice Test with Answers (Part - 16)

    Sep 07, 26 11:23 AM

    Digital SAT Math Practice Test with Answers (Part - 16)

    Read More

  3. Digital SAT Math Practice Test with Answers (Part - 15)

    Aug 23, 26 12:24 PM

    digitalsatmath441.png
    Digital SAT Math Practice Test with Answers (Part - 15)

    Read More