Find the product of two binomials in each case.
Question 1 :
(c + d)(c - d)
Question 2 :
(x + 3)(x - 3)
Question 3 :
(y + √5)(x - √5)
Question 4 :
(3p + 5q)(3p - 5q)
Question 5 :
(x2 + 2y)(x2 - 2y)
Question 6 :
(8 + z)(8 - z)
Question 7 :
(2 + √3x)(2 - √3x)
Question 8 :
(3 + 2z2)(3 + 2z2)
Question 9 :
(a2 + b2)(a2 - b2)
Question 10 :
(2x + yz)(2x - yz)
1. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = c and b = d.
(c + d)(c - d) = c2 - d2
2. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = x and b = 3.
(x + 3)(x - 3) = x2 - 32
= x2 - 9
3. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = y and b = √5.
(y + √5)(x - √5) = y2 - (√5)2
= y2 - 5
4. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = 3p and b = 5q.
(3p + 5q)(3p - 5q) = (3p)2 - (5q)2
= 9p2 - 25q2
5. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = x2 and b = 2y.
(x2 + 2y)(x2 - 2y) = (x2)2 - (2y)2
= x4 - 4y2
6. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = 8 and b = z.
(8 + z)(8 - z) = (8)2 - (z)2
= 64 - z2
7. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = 2 and b = √3x.
(2 + √3x)(2 - √3x) = 22 - (√3x)2
= 4 - 3x2
8. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = 3 and b = 2z2.
(3 + 2z2)(3 + 2z2) = (3)2 - (2z)2
= 9 - 4z2
9. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = a2 and b = b2.
(a2 + b2)(a2 - b2) = (a2)2 - (b2)2
= a4 - b4
10. Answer :
Use the rule for (a + b)(a - b).
(a + b)(a - b) = a2 - b2
Identify a and b : a = 2x and b = yz.
(2x + yz)(2x - yz) = (2x)2 - (yz)2
= 4x2 - y2z2
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