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Question 1 :
Check whether (2, -1) is a solution to the following equation.
x + 5y = -3
Question 2 :
Check whether (0, 3) is a solution to the following equation.
7x - y = 4
Question 3 :
Check whether (1, 1) is a solution to the system of equations given below.
2x + 3y = 5
3x - 5y = -2
Question 4 :
Check whether (2, -3) is a solution to the system of equations given below.
x - 2y = 8
2x + y = -1
Question 5 :
Find the value of k, if (2, 1) is a solution to the following equation.
2x +3y = k
Question 6 :
Check which of the following is a solution to the following equation.
x - 2y = 4
(A) (0, 2)
(B) (2, 0)
(C) (4, 0)
Question 7 :
Is (1, 3) a solution to this system of equations?
x + 4y = 13
5x + 4y = 17
Question 8 :
Given the system
3𝑥 − 2𝑦 = 5
2𝑥 + 3𝑦 = 38
which of the following ordered pairs is a solution?
A) (4, 9) B) (7, 8) C) (11, -3) D) (-5, 10)
Question 9 :
f ℎ(𝑥) =−(1/2) 𝑥 + 3, find h(−27).
A) 33/2 B) 30/3 C) 60 D) (27/2)
Question 10 :
List all the points which are a solution to 2x - y > 4
A) (0, -4) B) (6, 1) C) (-2, 4) D) (1, -2)

1. Answer :
x + 5y = -3
Substitute (2, -1) in the given equation.
2 + 5(-1) = -3 ?
2 - 5 = -3 ?
-3 = -3 ? True
Since the ordered pair (2, -1) makes the given equation true, it is a solution to the equation.
2. Answer :
7x - y = 4
Substitute (0, 3) in the given equation.
7(0) - 3 = 4 ?
0 - 3 = 4 ?
-3 = 4 ? False
Since the ordered pair (0, 3) does not make the given equation true, it is not a solution to the equation.
3. Answer :
2x + 3y = 5
3x - 5y = -2
Substitute (1, 1) in each equation in the given system.
|
2x + 3y = 5 x = 1 and y = 1 : 2(1) + 3(1) = 5 ? 2 + 3 = 5 ? 5 = 5 True |
3x - 5y = -2 x = 1 and y = 1 : 3(1) - 5(1) = -2 ? 3 - 5 = -2 ? -2 = -2 True |
Since the ordered pair (1, 1) makes both equations true, it is a solution to the system.
4. Answer :
x - 2y = 8
2x + y = -1
Substitute (2, -3) in each equation in the given system.
|
x - 2y = 8 x = 2 and y = -3 : 2 - 2(-3) = 8 ? 2 + 6 = 8 ? 8 = 8 True |
2x + y = -1 x = 2 and y = -3 : 2(2) - 3 = -1 ? 4 - 3 = -1 ? 1 = -1 False |
The ordered pair (2, -3) makes only the first equation true and it does not make the second one true
Since, the ordered pair (2, -3) does make both equations true, it is not a solution to the system.
5. Answer :
2x +3y = k
Substitute x = 2 and y = 1.
2(2) + 3(1) = k
7 = k
6. Answer :
(A) (0, 2) :
x - 2y = 4
Substitute x = 0 and y = 2.
0 - 2(2) = 4 ?
-4 = 4 False
Since the ordered pair (0, 2) does not make the given equation true, (0, 2) is not a solution to the equation.
(B) (2, 0) :
x - 2y = 4
Substitute x = 2 and y = 0.
2 - 2(0) = 4 ?
2 - 0 = 4 ?
2 = 4 False
Since the ordered pair (2, 0) does not make the given equation true, (2, 0) is not a solution to the equation.
(C) (4, 0) :
x - 2y = 4
Substitute x = 4 and y = 0.
4 - 2(0) = 4 ?
4 - 0 = 4 ?
4 = 4 True
Since the ordered pair (4, 0) makes the given equation true, (4, 0) is a solution to the equation.
7. Answer :
Substitute (1, 3) in each equation in the given system.
|
x + 4y = 13 x = 1 and y = 3 : 1 + 4(3) = 13 ? 1 + 12 = 13 ? 13 = 13 True |
5x + 4y = 17 x = 1 and y = 3 : 5(1) + 4(3) = 17 ? 5 + 12 = 17 ? 17 = 17 True |
Since the ordered pair (1, 3) makes both equations true, it is a solution to the system.
8. Answer :
3𝑥 − 2𝑦 = 5 -----(1)
2𝑥 + 3𝑦 = 38 -----(2)
Option A :
Applying the point (4, 9) in (1), we get
3(4) - 2(9) = 5
12 - 18 = 5
-6 ≠ 5
So, option A is not the solution for the system of linear equations.
Option B :
Applying the point (7, 8) in (1), we get
3(7) - 2(8) = 5
21 - 16 = 5
5 = 5
Applying in (2), we get
2(7) + 3(8) = 38
14 + 24 = 38
38 = 38
So, (7, 8) is the solution for the system of linear equations.
9. Answer :
ℎ(𝑥) =−(1/2) 𝑥 + 3, find h(−27).
Applying x = -27, we get
= (-1/2)(-27) + 3
= (27/2) + 3
= (27 + 6)/2
= 33/2
So, option A is correct.
10. Answer :
List all the points which are a solution to 2x - y > 4
|
Option A : (0, -4) 2(0) - (-4) > 4 0 + 4 > 4 (False) |
Option B : (6, 1) 2(6) - 1 > 4 12 - 1 > 4 13 > 4 (True) |
|
Option C : (-2, 4) 2(-2) - 4 > 4 -4 - 4 > 4 -8 > 4 (False) |
Option D : (1, -2) 2(1) - (-2) > 4 2 + 2 > 4 4 > 4 (False) |
(6, 1) is the solution
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