COMPLETE A TABLE OF VALUES GIVEN A FUNCTION RULE

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For the following input numbers, calculate output numbers under the given rules :

Question 1 :

Four times the input number.

Solution :

Let us consider "n" as input value and "m" as output value.

Rule ==> Four times the input number.

Formula :

m  =  4n

Input

n = 1

n = 2

n = 3

n = 4

Output

m  =  4(1) ==>  4

m  =  4(2) ==>  8

m  =  4(3) ==>  12

m  =  4(4) ==>  16

Completing the table :

Independent variable

(n)

1

2

3

4

Dependent variable

(m)

4

8

12

16

Question 2 :

The input number plus three.

Solution :

Rule ==> The input number plus three.

Formula :

m = n + 3

Input

n = 4

n = 6

n = 12

n = 26

Output

m  = 4+3  ==>  7

m  = 6+3  ==>  9

m  = 12+3  ==>  15

m  = 26+3  ==>  29

Completing the table :

Independent variable

(n)

4

6

12

26

Dependent variable

(m)

7

9

15

29

Question 3 :

Add two then multiply by 3

Solution :

Rule ==> Add two then multiply by 3

Formula :

m  =  3(n+2)

Input

n = 0

n = 1

n = 2

n = 5

Output

m  = 3(0+2)  ==>  6

m  = 3(1+2) ==>  9

m  = 3(2+2)  ==>  12

m  = 3(5+2)  ==>  21

Completing the table :

Independent variable

(n)

0

1

2

5

Dependent variable

(m)

6

9

12

21

Question 4 :

Multiply the input number by itself.

Solution :

Rule ==> Multiply the input number by itself.

Formula :

m  =  n ⋅ n

Input

n = 1

n = 2

n = 3

n = 5

Output

m  = 1 ⋅ 1  ==>  1

m  = 2 ⋅ 2  ==>  4

m  = 3 ⋅ 3  ==>  9

m  = 5 ⋅ 5  ==>  25

Completing the table :

Independent variable

(n)

1

2

3

5

Dependent variable

(m)

1

4

9

25

Question 5 :

Double the input number then add one.

Solution :

Rule ==> Double the input number then add one.

Formula :

m  =  2n+1

Input

n = 1

n = 2

n = 3

n = 8

Output

m  = 2(1)+1  ==>  3

m  = 2(2)+1  ==>  5

m  = 2(3)+1  ==>  7

m  = 2(8)+1  ==>  17

Completing the table :

Independent variable

(n)

1

2

3

8

Dependent variable

(m)

3

5

7

17

Question 6 :

Subtract 3 then multiply by 2.

Solution :

Rule ==> Subtract 3 then multiply by 2.

Formula :

m  =  2(n-3)

Input

n = 3

n = 4

n = 10

n = 15

Output

m  = 2(3-3)  ==>  0

m  = 2(4-3)  ==>  2

m  = 2(10-3)  ==>  14

m  = 2(15-3)  ==>  24

Completing the table :

Independent variable

(n)

3

4

10

15

Dependent variable

(m)

0

2

14

24

Complete each Function Table by calculating the output ‘y’ (or f(x)) for each input value ‘x’.

Question 7 :

complete-the-table-q1.png

Solution :

Applying each input, we get

  • When x = 0, y = 3x ==> y = 3(0) ==> 0
  • When x = 1, y = 3x ==> y = 3(1) ==> 3
  • When x = 2, y = 3x ==> y = 3(2) ==> 6
  • When x = 3, y = 3x ==> y = 3(3) ==> 9
  • When x = 4, y = 3x ==> y = 3(4) ==> 12

By applying all the values, we get

Independent variable

x

0

1

2

3

4

Dependent variable

y

0

3

6

9

12

Question 8 :

complete-the-table-q2.png

Solution :

Applying each input, we get

  • When x = -2, y = x + 2 ==> y = -2 + 2 ==> 0
  • When x = -1, y = x + 2 ==> y = -1 + 2 ==> 1
  • When x = 0, y = x + 2 ==> y = 0 + 2 ==> 2
  • When x = 1, y = x + 2 ==> y = 1 + 2 ==> 3
  • When x = 2, y = x + 2 ==> y = 2 + 2 ==> 4

By applying all the values, we get

Independent variable

(x)

-2

-1

0

1

2

Dependent variable

(y)

0

1

2

3

4

Question 9 :

Consider the function rule:

Multiply the input by two and then subtract one to get the output.

(a) Fill in the table for the inputs and outputs. Inputs are often designated by and outputs by .

Inputs are 0, 1, 2, 3

(b) Write an equation that gives this rule in symbolic form.

Solution :

Let x be the inputs 

Multiply the input by 2, then 2x

Then, subtract 1, we get

y = 2 x - 1

When input (x) = 0, then y = 2(0) - 1 ==> -1

When input (x) = 1, then y = 2(1) - 1 ==> 1

When input (x) = 2, then y = 2(2) - 1 ==> 3

When input (x) = 3, then y = 2(3) - 1 ==> 5

Completing the table,

Input (x)

0

1

2

3

Output (y)

-1

1

3

5

b) Rule in symbolic form is y = 2 x - 1.

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