Problem 1 :
Find the slope of the tangent to the curves at the respective given points.
(i) y = x4 + 2x2 − x at x = 1
(ii) x = a cos3t, y = b sin3t at t = π/2
Problem 2 :
Find the point on the curve y = x2 − 5x + 4 at which the tangent is parallel to the line 3x + y = 7 .
Problem 3 :
Find the points on the curve y = x3 − 6x2 + x + 3 where the normal is parallel to the line x + y = 1729.
Problem 4 :
Find the points on the curve y2 - 4xy = x2+ 5 for which the tangent is horizontal.
Problem 5 :
The normal at the point (1, 1) on the curve 2y + x2 = 3 is
(a) x + y = 0 (b) x - y = 0 (c) x + y + 1 = 0 (d) x - y = 0
Problem 6 :
Find the points on the curve
x2/9 + y2/16 = 1
at which the tangents are parallel to Y-axis
1) i) slope of the tangent at x = 1 is 7.
ii) slope of the tangent at x = π/2 is ∞
2) the required point is (1, 0).
3) the required points are (0, 3) and (4, -25).
4) the required points are (-2, 1) and (2, -1).
5) x - y = 0
6) the points at which the tangents are parallel to the y-axis are (3,0) and (−3,0).
Problem 1 :
Find the tangent and normal to the following curves at the given points on the curve.
(i) y = x2 - x4 at (1, 0)
(ii) y = x4 + 2ex at (0, 2)
(iii) y = x sin x at (π/2, π/2)
(iv) x = cost, y = 2 sin2t at t = π/3
Problem 2 :
Find the tangent and normal to the curve x3 + y3 = 2xy at (1, 1).
Problem 3 :
Consider the curve defined by 2y3 + 6x2 y - 12x2 + 6y = 1
i) Find dy/dx
ii) Write an equation of each horizontal tangent line to the curve.
iii) The line through the origin with slope -1 is tangent to the curve at point P. Find the x and y coordinate of P.
1) i) equation of normal is x - 2y - 1 = 0.
ii) equation of tangent is 2x - y + 2 = 0 and equation of normal is x + 2y - 4 = 0.
iii) equation of tangent x - y = 0
equation of normal x + y - π = 0
iv) Equation of tangent is 4x + 2y - 5 = 0
equation of normal is 2x - 4y + 5 = 0
2) i) equation of tangent is x + y = 2
equation of normal is x - y = 0
3) i) dy/dx = (- 2xy + 4x) / (y2 + x2 + 1)
ii) There are no points on the curve where y = 2.
iii) the required point is (-1/2, 1/2).
Problem 1 :
Find the equations of the tangents to the curve
y = 1+x3
for which the tangent is orthogonal with the line
x+12y = 12
Problem 2 :
Find the equations of the tangents to the curve
y = (x+1)/(x-1)
which are parallel to the line x+2y = 6.
Problem 3 :
Find the equation of tangent and normal to the curve given by
x = 7 cos t and y = 2 sin t for all t
at any point on the curve. Solution
Problem 4 :
Find the angle between the rectangular hyperbola xy = 2 and the parabola x2 + 4y = 0 .
Problem 5 :
Show that the two curves x2 − y2 = r2 and xy = c2 where c, r are constants, cut orthogonally
1) Equation of tangent is 12x - y - 15 = 0
Equation of normal is 12x - y + 17 = 0
2) Equation of tangent is x + 2y - 7 = 0
Equation of normal is x + 2y + 1 = 0
3) Equation of tangent is (2cost) x + (7sint)y = 14
Equation of normal is (7sint)x - (2cost)y - 45sint cost = 0
4) Equation of tangent is 12x + 36y = 227
5) Equation of tangent is x + 14y - 114 = 0
Equation of normal is x + 14y + 86 = 0
Example 1 :
Find the points on curve
x2-y2 = 2
at which the slope of the tangent is 2.
Example 2 :
Find at what points on a circle
x2+y2 = 13
the slope of the tangent is -2/3.
Example 3 :
For the curve y = 4x3 -2x5, find all the points at which the tangent passes through the origin.
Example 4 :
The curve
y = ax3 + bx2 + cx + 5
touches the x-axis at the point (-2, 0) and Cuts the y-axis at a point where the slope is 3. Find a, b, c
Example 5 :
The point on the curve y = x3 – 11x + 5 at which the tangent is y = x –11 is
Example 6 :
The line y = x + 1 is a tangent to the curve y2 = 4x at the point
(a) (1, 2) (b) (2, 1) (c) (1, – 2) (d) (–1 ,2)
1) the required points are
(2√(2/3), √(2/3)) and (-2√(2/3), - √(2/3))
2) the required points are (2, 3) (-2, -3).
3) points are (0, 0) (-1, -2) and (1, 2).
4) the values of a = -1/2, b = -3/4 and c = 3.
5) the required points are (-2, 19) and (2, 9).
6) (1, 2)
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