Problem 1 :
Find the missing term in 3 : 4 = 12 : __ .
Problem 2 :
Using 3 and 12 as means, write any two proportions.
Problem 3 :
Using 4 and 20 as means, write two proportions.
Problem 4 :
Show that 12 : 9, 4 : 3 are in proportion.
Problem 5 :
Solve for x :
5/3 = x/48
Problem 6 :
Solve for a :
18/a = 9/50
1. Answer :
3 : 4 = 12 : __
Let x be the missing term.
3 : 4 = 12 : x
Since the ratios 3 : 4 is equal to 12 : x, 3, 4, 12 and x are said to be in proportion.
That is,
Product of extremes = Product of means
3x = 4(12)
Divide both sides by 3.
x = 16
So, the missing term is 16.
2. Answer :
Given 3 and 12 are means.
Then,
__ : 3 = 12 : __
Let 'a' and 'b' be the missing terms.
The product of the means 3 x 12 = 36.
The product of Extremes (a x b) must be 36.
36 can be written as 2 x 18 or 4 x 9 etc,
2 : 3 = 12 : 18
4 : 3 = 12 : 9
3. Answer :
Given 3 and 12 are means.
Then,
__ : 4 = 20 : __
Let 'a' and 'b' be the missing terms.
The product of the means 4 x 20 = 80.
The product of Extremes (a x b) must be 80.
80 can be written as 16 x 5 or 10 x 8 etc,
16 : 4 = 20 : 5
10 : 4 = 20 : 8
4. Answer :
The product of the extremes = 12 x 3 = 36.
The product of the means = 9 x 4 = 36.
12 : 9, 4 : 3 are in proportion
(i.e.) 12 : 9 = 4 : 3
5. Answer :
5/3 = x/48
5(48) = x(3)
Divide both sides by 3.
80 = x
6. Answer :
18/a = 9/50
18(50) = a(9)
Divide both sides by 9.
100 = a
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