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SIMPLIFYING WITH TRIGONOMETRIC IDENTITIES

To simplify trigonometric identities, we have to remember the following problems.

Sometimes, we will be using the algebraic identities also to perform further simplification.

(a+b)2 = a2 + 2 ab + b2

(a-b)2 = a2 - 2 ab + b2

a2 - b2 = (a + b)(a - b)

Simplify.

Problem 1 :

tan x(csc x - sin x)

Solution :

tan x(csc x - sin x)

= sin xcos x(csc x - sin x))= sin xcos x1sin x - sin x= sin xcos x1 - sinx × sin xsin x = sin xcos x 1 - sin2xsin x= sin xcos x cos2xsin x= cos x tan x(csc x - sin x) = cos x

Problem 2 :

(csc x - 1) (csc x + 1)

Solution :

(csc x - 1) (csc x + 1)

= (csc2 x - 1) 

= cot2x

Problem 3 :

(sec x - tan x) (sec x + tan x)

Solution :

(sec x - tan x) (sec x + tan x)

= sec2 x - tan2 x

= 1

Problem 4 :

(1 + tan2x) (1 - sin2x)

Solution :

(1 + tan2x) (1 - sin2x)

= sec2x ⋅ cos2x

= (1/cosx)2 ⋅ cos2x

= (1/cos2x) ⋅ cos2x

= 1

(1 + tan2x) (1 - sin2x) = 1

Problem 5 :

cos x(csc x - secx) - cot x

Solution :

cos x(csc x - secx) - cot x

= cos x1sinx - sec x - cot x= cos x 1sin x - 1cos x - cot x= cos x 1sin x - 1cos x - cos xsin x= cos x cos x - sin xsin x cos x - cos xsin x= cos x - sin xsin x - cos xsin x= cos x - sin x - cos xsin x= -sin xsin x= -1

Problem 6 :

sin2 x(cot2x + 1)

Solution :

sin2 x(cot2x + 1)

= sin2 x(csc2x)

= sin2x(1/sin x)2

= sin2x(1/sin2x)

= 1

Problem 7 :

sin2x + sin2x cot2x

Solution :

sin2x + sin2x cot2x

= sin2x[1 + cot2x]

= sin2x ⋅ csc2x

= sin2x(1/sinx)2

= sin2x ⋅ (1/sin2x)

= 1

Problem 8 :

cot x sec x sin x

Solution :

cot x sec x sin x

= (cos x/sin x) ⋅ sec x ⋅ sin x

= (cos x/sin x) ⋅ (1/cos x) ⋅ sin x

= 1

Problem 9 :

cot2xcsc x - 1

Solution :

cot2xcsc x - 1= cos xsin x2csc x - 1= cos2xsin2xcsc x - 1= cos2xsin2x × 1csc x - 1=cos2xsin2x ×11sin x - 1 = cos2xsin2x × 11 - sin xsin x= cos2xsin2x × sin x1 - sin x= cos2xsin x × 11 - sin x= cos2xsin x(1 - sin x)= 1 - sin2xsin x(1 - sin x)= (1 + sin x) (1 - sin x)sin x(1 - sin x)= 1 + sin xsin x
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