Subscribe to our โถ๏ธ YouTube channel ๐ด for the latest videos, updates, and tips.
Problems 1-4 : Simplify using method I.
Problem 1 :
(2x/27y2)/(6x2/9)
Problem 2 :
(x/y + 1)/(1 - y/x)
Problem 3 :
[x/y - y/x] / [1/y2 - 1/x2]
Problem 4 :
[(1 + x2)1/2 - x2/(1 + x2)1/2] / (1 + x2)
Problems 5-8 : Simplify using method II.
Problem 5 :
(y/6x2) / (3/4y2)
Problem 6 :
[5x/(x + 2)]/[10/(x - 2)]
Problem 7 :
[x/y2 + 1/y] / [y/x2 + 1/x]
Problem 8 :
(x - y/3x) / (y + 1/9x2)
Problem 9 :

Problem 10 :

Problem 11 :


1. Answer :
= (2x/27y2)/(6x2/9)
The numerator of the compound fraction is already a single fraction, and so is the denominator.
Invert the the fraction in denominator and multiply.
= (2x/27y2) โ (9/6x2)
= (2x โ 9) / (6x2 โ 27y2)
Cancel common factors.
= 1 / (3x โ
3y2)
= 1/9xy2
2. Answer :
= (x/y + 1)/(1 - y/x)
We combine the terms in the numerator into a single fraction and do the same in the denominator. Then we invert and multiply.
= [(x + y)/y]/[(x - y)/x]
Invert the the fraction in denominator and multiply.
= [(x + y)/y)] โ [x/(x - y)]
= [x(x + y)] / [y(x - y)]
3. Answer :
= [x/y - y/x] / [1/y2 - 1/x2]
We combine the terms in the numerator into a single fraction and do the same in the denominator. Then we invert and multiply.
= [(x2 - y2)/xy] / [(x2 - y2)/x2y2]
Invert the the fraction in denominator and multiply.
= [(x2 - y2)/xy] โ [x2y2/(x2 - y2)]
= [(x2 - y2)x2y2] / [xy(x2 - y2)]
Cancel common factors.
= xy
4. Answer :
= [(1 + x2)1/2 - x2/(1 + x2)1/2] / (1 + x2)
We combine the terms in the numerator into a single fraction and do the same in the denominator. Then we invert and multiply.
= [{(1 + x2) - x2}/(1 + x2)1/2] / (1 + x2)
= [(1 + x2 - x2)/(1 + x2)1/2] / (1 + x2)
= [1/(1 + x2)1/2] / (1 + x2)
Invert the the fraction in denominator and multiply.
= [1/(1 + x2)1/2] โ [1/(1 + x2)]
= 1/[(1 + x2)1/2(1 + x2)]
= 1/(1 + x2)1/2 + 1
= 1/(1 + x2)3/2
5. Answer :
= (y/6x2) / (3/4y2)
The least common denominator of the fractions in both numerator and denominator is 12x2y2.
Multiply numerator and denominator by the LCD.
= (y/6x2)(12x2y2) / (3/4y2)(12x2y2)
Simplify.
= 2y3/9x2
6. Answer :
= [5x/(x + 2)]/[10/(x - 2)]
The least common denominator of the fractions in both numerator and denominator is (x + 2)(x - 2).
Multiply numerator and denominator by the LCD.
= [5x/(x + 2)](x + 2)(x - 2) / [10/(x - 2)](x + 2)(x - 2)
Simplify.
= [5x(x - 2)]/[10(x + 2)]
= x(x - 2)/2(x + 2)
7. Answer :
= [x/y2 + 1/y] / [y/x2 + 1/x]
The least common denominator of the fractions in both numerator and denominator is x2y2.
Multiply numerator and denominator by the LCD.
= [x/y2 + 1/y](x2y2) / [y/x2 + 1/x](x2y2)
Use the distributive property.
= [x/y2 โ x2y2 + 1/y โ x2y2] / [y/x2 โ x2y2 + 1/x โ x2y2]
Simplify.
= [x3 + x2y]/[y3 + xy2]
Factor.
= [x2(x + y)]/[y2(y + x)]
= x2/y2
8. Answer :
= (x - y/3x) / (y + 1/9x2)
The least common denominator of the fractions in both numerator and denominator is 18x2.
Multiply numerator and denominator by the LCD.
= (x - y/3x)(18x2) / (y + 1/9x2)(18x2)
Use the distributive property.
= (x โ
18x2 - y/3x โ
18x2) / (y โ
18x2 + 1/9x2 โ
18x2)
Simplify.
= (18x3 - 6xy)/(18x2y + 2)
Factor.
= [2x(9x2 - 3y)]/[2(9x2y + 1)]
= x(9x2 - 3y)]/(9x2y + 1)
9. Answer :

Simplifying numerator :
= 4/(5 - x) + 5/(x - 5)
= -4/(x - 5) + 5/(5 - x)
= (-4 + 5)/(x - 5)
= 1/(x - 5)
Simplifying denominator :
= 2/x + 3/(x - 5)
= [2(x - 5) + 3x] / (x - 5)
= [2x - 10 + 3x] / (x - 5)
= [5x - 10] / (x - 5)
= 5(x - 2) / (x - 5)
Dividing the numerator and denominator, we get
= [1/(x - 5)] รท [5(x - 2) / (x - 5)]
= [1/(x - 5)] x [(x - 5) / 5(x - 2)]
= 1/5(x - 2)
10. Answer :

Simplifying numerator :
= 3/(x - 4) - 2/(4 - x)
= 3/(x - 4) + 2/(x - 4)
= (3 + 2) / (x - 4)
= 5/(x - 4)
Simplifying denominator :
= 2/(x - 4) - (2/x)
= [2x - 2(x - 4)]/x(x - 4)
= [2x - 2x + 8]/x(x - 4)
= 8/x(x - 4)
Dividing the numerator and denominator, we get
= [5/(x - 4)] รท [8/x(x - 4)]
= [5/(x - 4)] x [x(x - 4)/8]
5/8x
11. Answer :

Simplifying numerator :
= (x + 2)/x - 2/(x - 1)
Least common multiple for the denominators are x(x - 1)
= [(x + 2)(x - 1) - 2x]/x(x - 1)
= [(x2 - x + 2x - 2) - 2x]/x(x - 1)
= [(x2 + x - 2) - 2x]/x(x - 1)
= (x2 + x - 2 - 2x)/x(x - 1)
= (x2 - x - 2)/x(x - 1)
Simplifying denominator :
= (x + 1)/x - [(x + 1)/(x - 1)]
= [(x + 1)(x - 1) - x(x + 1)]/x(x - 1)
= [(x2 - 1) - (x2 + x)]/x(x - 1)
= [x2 - 1 - x2 - x]/x(x - 1)
= -(x + 1) / x(x - 1)
Dividing the numerator and denominator, we get
= (x2 - x - 2)/x(x - 1) รท [-(x + 1) / x(x - 1)]
= [(x2 - x - 2)/x(x - 1)] x [-x(x - 1)/(x + 1)]
= -(x2 - x - 2)/(x + 1)
= -(x2 - 2x + x - 2)/(x + 1)
= -(x - 2)(x + 1)/(x + 1)
= -(x - 2)
Subscribe to our โถ๏ธ YouTube channel ๐ด for the latest videos, updates, and tips.
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
ยฉAll rights reserved. onlinemath4all.com
Dec 08, 25 12:12 AM
Dec 05, 25 04:04 AM
Dec 03, 25 07:02 AM