**Simple Interest Examples :**

In this section, we are going to see some solved examples on simple interest.

Before look at the examples, let us see the definition and key concept of simple interest.

**Definition of Simple Interest :**

Simple interest is the interest computed on the principal for the entire period of borrowing. It is calculated on the outstanding principal balance and not on interest previously earned. It means no interest paid on interest earned during the term of loan.

**Key Concept :**

**Principal will always be constant****Interest for every year will be same**

Formula to find Simple Interest :

**I = Prt**

** P** = Principal (initial value of an investment)

** r** = Annual interest rate

** ****t** = number of years

**Problem 1 :**

Lily wants to have an interest income of $3,000 a year. How much must she invest for one year at 8% ?

**Solution : **

Formula for simple interest is

I = Prt

Here, I = 3000, t = 1, r = 8%

Let us plug these values in the above formula

3000 = P ⋅ 8/100 ⋅ 1

3000 = P ⋅ 2/25

Multiply both sides by 25/2.

25/2 ⋅ 3000 = P

37500 = P

Hence, Lily she must invest $37,500.

Let us look at the next problem on "Simple interest examples".

**Problem 2 :**

Alex owes the bank some money at 4% per year. After half a year, he paid $45 as interest. How much money does she owe the bank ?

**Solution : **

Formula for simple interest is

I = Prt

Here, I = 45, t = 1/2, r = 4%

Let us plug these values in the above formula

45 = P ⋅ 4/100 ⋅ 1/2

45 = P ⋅ 1/50

Multiply both sides by 50.

50 ⋅ 45 = P

2250 = P

Hence, Lily she must invest $2,250.

Let us look at the next problem on "Simple interest examples".

**Problem 3 :**

How long does it take a principal of $25,000 at a simple interest rate of 5% to become $30,000 ?

**Solution : **

Interest earned (I) = Amount - Principal

I = $30,000 - $25,000

I = $5,000

Formula for simple interest is

I = Prt

Here, P = 25000, I = 5000, r = 5%

Let us plug these values in the above formula

5000 = 25000 ⋅ 5/100 ⋅ t

5000 = 1250 ⋅ t

Divide both sides by 1250.

5000 / 1250 = t

4 = t

Hence, it will take 4 years for the principal of $25,000 at a simple interest rate of 5% to become $30,000.

Let us look at the next problem on "Simple interest examples".

**Problem 4 :**

$45,000 is deposited into a savings account. After one year, 4 months and 20 days it totals $52,500. Calculate the simple interest rate for this account.

**Solution : **

**Given :** Time period is 1 year, 4 months

1 year, 4 months = 1 4/12 years

1 year, 4 months = 1 ⅓ years

1 year, 4 months = 4/3 years

So, the time period is 4/3 years.

Interest earned (I) = Amount - Principal

I = $52,500 - $45,000

I = $7,500

Formula for simple interest is

I = Prt

Here, P = 45000, I = 7500, t = 4/3

Let us plug these values in the above formula

7500 = 45000 ⋅ r ⋅ 4/3

7500 = 60000 ⋅ r

Divide both sides by 60000.

7500 / 60000 = r

0.125 = r

To convert the decimal 0.125 into percentage, multiply it by 100.

12.5% = r

Hence, the simple interest rate for the given account is 12.5%.

Let us look at the next problem on "Simple interest examples".

**Problem 5 :**

Mr. Berman put his savings into two accounts, which pay 6% and 9% annual rate. If he invested a total of $22,000 and received $1440 as interest after one year. How much did he put into each account ?

**Solution : **

Let "x" be the amount invested at 6% annual rate

Then, the amount invested at 9% annual rate is

= 22000 - x

**Given :** Total interest received after one year is $1440.

So, we have

Interest at 6% rate + Interest at 9% rate = 1440

x ⋅ 6/100 ⋅ 1 + (22000 - x) ⋅ 9/100 ⋅ 1 = 1440

0.06x + (22000 - x)0.09 = 1440

0.06x + 1980 - 0.09x = 1440

1980 - 0.03x = 1440

1980 - 1440 = 0.03x

540 = 0.03x

Divide both sides by 0.03

540 / 0.03 = x

54000 / 3 = x

18000 = x

And also,

22000 - x = 22000 - 18000

24000 - x = 4000

Hence, the amount invested at 6% rate is $18,000 and at 9% rate is $4,000.

Let us look at the next problem on "Simple interest examples".

**Problem 6 :**

Mr. George invests his inheritance of $30,000 in two different accounts which pay 7% and 9% annual interest. It is given that he gets more interest at 9% rate than 7% rate. After one year, if the difference between the interest received in two accounts is $140, find the amount invested in each account.

**Solution : **

Let "x" be the amount invested at 7% annual rate.

Then, the amount invested at 9% annual rate is

= 30000 - x

After one year, interest earned at 7% rate is

= x ⋅ 7/100 ⋅ 1

= 0.07x -----(1)

After one year, interest earned at 9% rate is

= (30000 - x) ⋅ 9/100 ⋅ 1

= (30000 - x) ⋅ 0.09

= 2700 - 0.09x -----(2)

**Given :** Difference between the interest received in two accounts is $140 and also interest received at 9% is more than 7%

That is, (2) > (1).

So, we have

(2) - (1) = 140

2700 - 0.09x - 0.07x = 140

2700 - 0.16x = 140

2700 - 140 = 0.16x

2560 = 0.16x

Divide both sides by 0.16

2560 / 0.16 = x

256000 / 16 = x

16000 = x

And also,

30000 - x = 30000 - 16000

30000 - x = 14000

Hence, the amount invested at 7% rate is $16,000 and at 9% rate is $14,000.

Let us look at the next problem on "Simple interest examples".

**Problem 7 :**

In simple interest, a sum of money doubles itself in 10 years. Find the number of years it will take to triple itself.

**Solution : **

Let P be the sum of money invested.

Given : Sum of money doubles itself in 10 years

Then, P will become 2P in 10 years.

Now we can calculate interest for ten years as given below

From the above calculation, P is the interest for the first 10 years.

In simple interest, interest earned will be same for every year.

So, interest earned in the next 10 years also will be P.

It has been explained below.

Hence, it will take 20 years for the principal to become triple itself.

Let us look at the next problem on "Simple interest examples".

**Problem 8 :**

In simple interest, a sum of money amounts to $ 6200 in 2 years and $ 7400 in 3 years. Find the principal.

**Solution :**

At the end of 2 years, we get $6200

At the end of 3 years, we get $7400

From these two information, we can get the interest earned in the 3rd year as given below.

In simple interest, interest will be same for every year.

Based on this, we can calculate the principal as given below.

Hence, the principal is $3800.

After having gone through the stuff examples given above, we hope that the students would have understood the stuff "Simple interest".

Apart from the stuff given above, If you want to know more about "Simple interest", please click here

Apart from the stuff given in this section, if you need any other stuff in math, please use our google custom search here.

Widget is loading comments...

You can also visit our following web pages on different stuff in math.

**WORD PROBLEMS**

**Word problems on simple equations **

**Word problems on linear equations **

**Word problems on quadratic equations**

**Area and perimeter word problems**

**Word problems on direct variation and inverse variation **

**Word problems on comparing rates**

**Converting customary units word problems **

**Converting metric units word problems**

**Word problems on simple interest**

**Word problems on compound interest**

**Word problems on types of angles **

**Complementary and supplementary angles word problems**

**Markup and markdown word problems **

**Word problems on mixed fractrions**

**One step equation word problems**

**Linear inequalities word problems**

**Ratio and proportion word problems**

**Word problems on sets and venn diagrams**

**Pythagorean theorem word problems**

**Percent of a number word problems**

**Word problems on constant speed**

**Word problems on average speed **

**Word problems on sum of the angles of a triangle is 180 degree**

**OTHER TOPICS **

**Time, speed and distance shortcuts**

**Ratio and proportion shortcuts**

**Domain and range of rational functions**

**Domain and range of rational functions with holes**

**Graphing rational functions with holes**

**Converting repeating decimals in to fractions**

**Decimal representation of rational numbers**

**Finding square root using long division**

**L.C.M method to solve time and work problems**

**Translating the word problems in to algebraic expressions**

**Remainder when 2 power 256 is divided by 17**

**Remainder when 17 power 23 is divided by 16**

**Sum of all three digit numbers divisible by 6**

**Sum of all three digit numbers divisible by 7**

**Sum of all three digit numbers divisible by 8**

**Sum of all three digit numbers formed using 1, 3, 4**

**Sum of all three four digit numbers formed with non zero digits**

**Sum of all three four digit numbers formed using 0, 1, 2, 3**

**Sum of all three four digit numbers formed using 1, 2, 5, 6**

Widget is loading comments...