The set of positive integers {a, b, c} is a Pythagorean triple if it obeys the rule
a2 + b2 = c2
Example 1 :
Show that {5, 12, 13} is a Pythagorean triple
Solution :
From the given numbers, the largest number is 13.
132 = 52 + 122
169 = 25 + 144
169 = 169
So, {5, 12, 13} is a Pythagorean triple.
Example 2 :
Find k if {9, k, 15} is a Pythagorean triple.
Solution :
Let 92 + k2 = 152
81 + k2 = 225
k2 = 144
k = √144
k = 12
Example 3 :
For what values of n does {n, n+1, n+2} form a Pythagorean triple?
Solution :
Let n2 + (n+1)2 = (n+2)2
n2+n2+2n+1 = n2+4n+4
2n2-n2+2n-4n+1-4 = 0
n2-2n-3 = 0
(n-3)(n+1) = 0
n = 3 and n = -1
So, for n = 3 the given set will create Pythagorean triple.
Example 4 :
Show that {n, n+1, n+3} cannot form a Pythagorean triple.
Solution :
Let n2 + (n+1)2 = (n+3)2
n2+n2+2n+1 = n2+6n+9
2n2-n2+2n-5n+1-9 = 0
n2-3n-8 = 0
It is not factorable. So, by solving this quadratic equation, we will not get integer value for n.
Therefore the given set of numbers will not create Pythagorean triple.
Example 5 :
Write a Pythagorean triplet whose one number is 12.
Solution :
For any natural number where, “m” > 1
m2 - 1 = 12
m2 = 12 + 1
m2 = 13 (the value of m is not an integer)
Then, let 2m = 12
m = 6
m2 - 1 = 62 - 1 = 36 - 1 = 35 |
m2 + 1 = 62 +- 1 = 36 + 1 = 37 |
So, the required Pythagorean triplets are 12, 36 and 37.
Example 5 :
Write a Pythagorean triplet where the smallest number is 6.
Solution :
For any natural number where, “m” > 1
m2 - 1 = 6
m2 = 6 + 1
m2 = 7
Here m is not an integer. Then,
m2 + 1 = 6
m2 = 6 - 1
m2 = 5
Here m is not an integer. Then,
2m = 6
m = 3 (is an integer)
m2 - 1 = 32 - 1 = 9 - 1 = 8 |
m2 + 1 = 32 + 1 = 9 + 1 = 10 |
So, the Pythagorean triples are 3, 8 and 10.
Example 6 :
What is the Pythagorean triples of two positive numbers 5 and 12 ?
Solution :
When two numbers in Pythagorean triples are given, the numbers are
m2 - n2, 2mn and m2 + n2
m2 - n2 = 122 - 52
= 144 - 25
= 119
2mn = 2(12)(5)
= 24(5)
= 120
m2 + n2 = 122 + 52
= 144 + 25
= 169
So, the required Pythagorean Triplet for the given values are 119, 120 and 169.
Example 7 :
Out of the dates given below which date constitutes a Pythagorean triplet ?
A) 15/08/17 B) 16/08/16 C) 3/5/17 D) 4/9/15
Solution :
Option A :
15/08/17
Let 2m = 8
m = 4
m2 - 1 = 42 - 1 = 16 - 1 = 15 |
m2 + 1 = 42 + 1 = 16 + 1 = 17 |
So, date A is Pythagorean Triplet.
Example 8 :
In a right angled triangle, if sum of the squares of the sides making right angle is 169 then what is the length of the hypotenuse?
A) 15 B) 13 C) 5 D) 12
Solution :
The numbers which are in Pythagorean triplets, the sum of the squares of two numbers will be equal to the square of Hypotenuse.
Let h be the square of hypotenuse.
h2 = 169
h = √169
h = 13 cm
So, the length of hypotenuse is 13 cm.
Example 9 :
Out of the following, which is the Pythagorean triplet?
A) (1, 5, 10) B) (3, 4, 5) C) (2, 2, 2) D) (5, 5, 2)
Solution :
Option A :
(1, 5, 10)
2m = 10
m = 5
m2 - 1 = 52 - 1 = 25 - 1 = 24 |
m2 + 1 = 52 + 1 = 25 + 1 = 26 |
So, option A is incorrect.
Option B :
(3, 4, 5)
2m = 4
m = 2
m2 - 1 = 22 - 1 = 4 - 1 = 3 |
m2 + 1 = 22 + 1 = 4 + 1 = 5 |
So, option B is correct.
Example 10 :
The hypotenuse of right angled triangle with perpendicular sides 4 and 5 is _________.
A) 41 B) √41 C) 6 D) None of the above
Solution :
Let a = 4 and b = 5 and c be the hypotenuse.
Square of hypotenuse = sum of squares of remaining two sides.
42 + 52 = c2
c2 = 16 + 25
c2 = 41
c = √41
Kindly mail your feedback to v4formath@gmail.com
We always appreciate your feedback.
©All rights reserved. onlinemath4all.com
Oct 17, 25 07:27 PM
Oct 16, 25 06:04 AM
Oct 14, 25 10:57 AM