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Question 1 :
Order β22, Ο + 1 and 4 1/2 from least to greatest. Then graph them on the number line.
Question 2 :
Order 4β2, 2β3, 3β2, β17, 3β3 and 5 from least to greatest.

Question 1 :
Order β22, Ο + 1 and 4 1/2 from least to greatest. Then graph them on the number line.
Answer :
Step 1 :
First approximate β22.
β22 is between 4 and 5. Since we donβt know where it falls between 4 and 5, we need to find a better estimate for β22.
So that we can compare it to 4 1/2.
Since 22 is closer to 25 than 16, use squares of numbers between 4.5 and 5 to find a better estimate of β22.
4.52 = 20.25
4.62 = 21.16
4.72 = 22.09
4.82 = 23.04
Since 4.72 = 22.09, an approximate value for β22 is 4.7.
That is,
β22 β 4.7 -----(1)
Step 2 :
An approximate value of Ο is 3.14. So an approximate value of Ο+1 is 4.14.
That is,
Ο + 1 β 4.14 -----(2)
Step 3 :
The value of 4 1/2 is 4.5.
That is,
4 1/2 = 4.5 -----(3)
Step 4 :
Comparing (1), (2) and (3), we can order the numbers from least to greatest as given below.
Ο + 1, 4 1/2 and β22
Step 5 :
Read the numbers from left to right to place them on a number line in order from least to greatest.

Question 2 :
Order 4β2, 2β3, 3β2, β17, 3β3 and 5 from least to greatest.
Answer :
Key Concept :
Most of the given numbers are irrational numbers.
So, square the given numbers and order them from least to greatest.
Step 1 :
Take square to 4β2.
(4β2)2 = (4)2(β2)2
(4β2)2 = (16)(2)
(4β2)2 = 32 -----(1)
Step 2 :
Take square to 2β3.
(2β3)2 = (2)2(β3)2
(2β3)2 = (4)(3)
(2β3)2 = 12 -----(2)
Step 3 :
Take square to 3β2.
(3β2)2 = (3)2(β2)2
(3β2)2 = (9)(2)
(3β2)2 = 18 -----(3)
Step 4 :
Take square to β17.
(β17)2 = 17 -----(4)
Step 5 :
Take square to 3β3.
(3β3)2 = (3)2(β3)2
(3β3)2 = (9)(3)
(3β3)2 = 27 -----(5)
Step 6 :
Take square to 5.
(5)2 = 25 -----(6)
Step 7 :
Comparing (1), (2), (3), (4), (5) and (6), we can write the squares of the given irrational numbers from least to greatest as given below.
12, 17, 18, 25, 27, 32
In the above order, write the corresponding real number to its square to write the given real numbers in the order from least to greatest.
2β3, β17, 3β2, 5, 3β3, 4β2
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