Subscribe to our ▶️ YouTube channel 🔴 for the latest videos, updates, and tips.

MULTIPLYING MONOMIALS EXAMPLES

To multiply two or more monomials, we have to follow the rule given below.

(i) Multiply the signs

(ii) Multiply the coefficients

(iii) Multiply the variables.

Problem 1 :

(3x²) (7x³)

Solution :

= (3x²) (7x³)

Multiplying the coefficients and multiplying variables together, we get

= (3 ∙ 7) (x² ∙ x³)

Use the product of power property.

= 21x2+3

= 21x5

Problem 2 :

8m5 ∙ m

Solution :

= 8m5 ∙ m

Multiplying the coefficients and multiplying variables together, we get


= (8 ∙ 1) (m5 ∙ m1)

Use the product of power property.

= 8m5+1

= 8m6

Problem 3 :

t³ ∙ 6t7

Solution :

= t³ ∙ 6t7

Group factors with like bases together.

= (1 ∙ 6) (t³ ∙ t7)

Multiplying the coefficients and multiplying variables together, we get

Use the product of power property.

= 6t3+7

= 6t10

Problem 4 :

(4y4) (-9y²)

Solution :

= (4y4) (-9y²)

Multiplying the coefficients and multiplying variables together, we get

= (4 ∙ -9) (y4 ∙ y²)

Use the product of power property.

= - 36y4+2

= - 36y6

Problem 5 :

3r5 ∙ 2r² ∙7r6

Solution :

= 3r5 ∙ 2r² ∙7r6

Multiplying the coefficients and multiplying variables together, we get

= (3 ∙ 2 ∙ 7) (r5 ∙ r² ∙ r6)

Use the product of power property.

= 42r5+2+6

= 42r13

Problem 6 :

(-2p³r) (11r4p6)

Solution :

= (-2p³r) (11r4p6)

Multiplying the coefficients and multiplying variables together, we get

= (-2 ∙ 11) (p³ ∙ p6 ∙ r ∙ r4)

Use the product of power property.

= -22p (3+6) r (1+4)

= -22p9r5

Problem 7 :

(6y³x) (5y³)

Solution :

= (6y³x) (5y³)

Multiplying the coefficients and multiplying variables together, we get

= (6 ∙ 5) (x ∙ y³ ∙ y³)

Use the product of power property.

= 30xy3+3

= 30xy6

Problem 8 :

7c5a³b ∙ 8a²b4c

Solution : 

= 7c5a³b ∙ 8a²b4c

Multiplying the coefficients and multiplying variables together, we get

= (7 ∙ 8) (a³ ∙ a² ∙ b ∙ b4 ∙ c5 ∙ c)

Use the product of power property.

= (7 ∙ 8) (a (2+3) b (1+4) c (5+1))

= 56a5b5c6

Problem 9 :

(-3t³u²) (-4u³t)

Solution :

= (-3t³u²) (-4u³t)

Multiplying the coefficients and multiplying variables together, we get

= (-3 ∙ -4) (t³ ∙ t ∙ u² ∙ u³)

Use the product of power property.

= (-3 ∙ -4) (t (3+1) u (2+3))

= 12t4u5

Problem 10 :

9/4 z6 × 4/27 z7 × 1/2 z²

Solution :

= 9/4 z6 × 4/27 z7 × 1/2 z²

Multiplying the coefficients and multiplying variables together, we get

= (9/4 ∙ 4/27 ∙ 1/2) (z6 ∙ z7 ∙ z²)

Use the product of power property.

= 1/6 z (6+7+2)

= 1/6 z15

Problem 11 :

-5/7 q4 × -7/5 q6

Solution :

= -5/7 q4 × -7/5 q6

Multiplying the coefficients and multiplying variables together, we get

= (-5/7 ∙ -7/5) (q4 ∙ q6)

Use the product of power property.

= 1 ∙ q4+6

= q10

Problem 12 :

6v² × -8v7

Solution :

= 6v² × -8v7

Group factors with like bases together.

= (6 ∙ -8) (v² ∙ v7)

Use the product of power property.

= - 48v2+7

= - 48v9

onlinemath4all_official_badge1.png

Recent Articles

  1. AP Calculus BC Problems with Solutions

    Sep 30, 26 01:08 PM

    digitalsatmath451.png
    AP Calculus BC Problems with Solutions

    Read More

  2. Digital SAT Math Practice Test with Answers (Part - 17)

    Sep 30, 26 01:00 PM

    digitalsatmath444.png
    Digital SAT Math Practice Test with Answers (Part - 17)

    Read More

  3. Digital SAT Math Practice Test with Answers (Part - 16)

    Sep 07, 26 11:23 AM

    Digital SAT Math Practice Test with Answers (Part - 16)

    Read More