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Lily purchased 2.5 lbs fruits at the rate of $3.50 per lb. How much money should she pay?
Certainly it would be $(2.5 × 3.50). Both 2.5 and 3.5 are decimal numbers.
Now, we have come across a situation where we need to know how to multiply two decimals. So we now learn the multiplication of two decimal numbers.
Now, let us find 1.5 x 4.3.
Multiplying 15 and 43, we get 645.
In both 1.5 and 4.3, there is 1 digit to the right of the decimal point. So, count 2 digits from the right and put a decimal point.
So, we get 1.5 x 4.3 = 6.45.
While multiplying 1.43 and 2.1, you will first multiply 143 and 21. For placing the decimal in the product obtained, you will count 2 + 1 = 3 digits starting from the right most digit.
Thus 1.43 x 2.1 = 3.003.
Problem 1 :
Evaluate :
4.8 x 5.2
Solution :
In 4.8 and 5.2, ignore the decimal points and consider them as if they were integers. That is, 48 and 52.
Multiply 48 and 52.
48 x 52 = 2496
In both 4.8 and 5.2, there is 1 digit to the right of the decimal point. So, in the result 2496, count 2 digits from the right and put a decimal point.
Therefore,
4.8 x 5.2 = 24.96
Problem 2 :
Evaluate :
0.25 x 6.8
Solution :
In 0.25 and 6.8, ignore the decimal points and consider them as if they were integers. That is, 25 and 68.
Multiply 25 and 68.
25 x 68 = 1700
In 0.25, there are 2 digits to the right of the decimal point and in 6.8, there is 1 digit to the right of the decimal point, total 3 digits. So, in the result 1700, count 3 digits from the right and put a decimal point.
Therefore,
0.25 x 6.8 = 1.700
= 1.7
Note :
To the right of a decimal point, zeros at the end need not be considered.
Problem 3 :
If the length of each side of a square is 3.2 cm, find its perimeter.
Solution :
All the sides of a square are equal.
Length of each side = 3.2 cm.
Perimeter of a square = 4 x length of each side
Thus, perimeter :
= 4 × 3.2
= 12.8 cm.
Problem 4 :
If the length of each side of a square is 2.8 cm, find its area.
Solution :
Area of a square = side x side
Length of each side = 2.8 cm.
= 2.8 x 2.8
= 7.84 cm2
Problem 5 :
The length of a rectangle is 5.8 cm and its width is 2.5 cm. What is the area of the rectangle?
Solution :
Area of a rectangle = length x width
Length = 5.8 cm. and width = 2.5 cm.
= 5.8 x 2.5
= 14.5 cm2
Problem 6 :
The length of a rectangle is 6.3 cm and its width is 3.2 cm. What is the perimeter of the rectangle?
Solution :
Perimeter of the rectangle = 2(length + width)
Length = 6.3 cm. and width = 3.2 cm.
= 2(6.3 + 3.2)
= 2(9.5)
= 19 cm
Problem 7 :
The radius of a circle is 6.5 cm. Find its circumference using π ≈ 3.14.
Solution :
Circumference of a circle = 2πr
Substitute π ≈ 3.14 and r = 6.5.
≈ 2 x 3.14 x 6.5
= 40.82
Circumference of the circle is about 40.82 cm.
Problem 8 :
The radius of a circle is 7.5 cm. Find its area using π ≈ 3.14.
Solution :
Area of a circle = πr2
Substitute π ≈ 3.14 and r = 7.5.
≈ 3.14 x 7.52
= 3.14 x 56.25
= 176.625
Area of the circle is about 176.625 square cm.
Problem 9 :
What is 45% of 78.2?
Solution :
45% of 78.2 = 45% x 78.2
= (45/100) x 78.2
= 0.45 x 78.2
= 35.19
Problem 10 :
What is 2.5% of 15.6?
Solution :
2.5% of 15.6 = 2.5% x 15.6
= (2.5/100) x 15.6
= 0.025 x 15.6
= 0.39
Lily observed that
1.9 = 19/10
1.97 = 197/100
1.973 = 1973/1000
Thus, she found that depending on the position of the decimal point the decimal number can be converted to a fraction with denominator 10 , 100 or 1000.
Now let us see what would happen if a decimal number is multiplied by 10 or 100 or 1000.
For example,
2.97 x 10 = (297/100) x 10 = 297/10 = 29.7
Decimal point shifted to the right by one place, since 10 has one zero.
2.97 x 100 = (297/100) x 100 = 297
Decimal point shifted to the right by two places, since 100 has two zeros.
2.97 x 1000 = (297/100) x 1000 = 297 x 10 = 2970
Decimal point shifted to the right by three places, since 1000 has three zeros.


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