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Let us consider a power with positive integer exponent, say 53. To simplify 53, use 5 as a factor two times :
53 = 5 โ 5 โ 5 = 125
If the exponent is negative or zero, what does it mean ?
A table can be used to look for a pattern to figure it out.

When the exponent decreases by one, the value of the power is divided by 5. Continue the pattern of dividing by 5.
50 = 5/5 = 1
5-1 = 1/5 = 1/51
5-2 = 1/5 รท 5 = 1/52
Words :
Any nonzero number raised to the zero power is 1.
Numbers :
50 = 1
(-5)0 = 1
2150 = 1
(2/3)0 = 1
Algebra :
If x โ 0, then x0 = 1.
Words :
Any nonzero number raised to a negative exponent is equal to 1 divided by that number raised to the opposite (positive) exponent.
Numbers :
5-2 = 1/52 = 1/25
2-4 = 1/24 = 1/16
Algebra :
If x โ 0 and n is an integer, then x-n = 1/xn.
The diameter for a piston could vary by at most 10-3 inch.
Simplify this expression.
10-3 = 1/103 = 1/(10 โ 10 โ 10) = 1/1000
10-3 inch is equal to 1/1000 inch, or 0.0001 inch.
Example 1 :
Simplify :
2-3
Solution :
= 2-3
= 1 / 23
= 1 / (2 โ 2 โ 2)
= 1/8
Example 2 :
Simplify :
70
Solution :
= 70
Any non zero number raised to the zero power is 1.
= 1
Example 3 :
Simplify :
(-3)-4
Solution :
= (-3)-4
= 1 / (-3)4
= 1 / [(-3)(-3)(-3)(-3)]
= 1/81
Example 4 :
Simplify :
-3-4
Solution :
= -3-4
= -1 / 34
= -1 / (3 โ 3 โ 3 โ 3)
= -1/81
Example 5 :
Evaluate x-1 for x = 3.
Solution :
= x-1
Substitute 3 for x.
= 3-1
= 1/3
Example 6 :
Evaluate x0y-3 for x = 8 and y = -2.
Solution :
= x0y-3
Substitute 0 for x and -2 for y.
= 80 โ (-2)-3
= 1 โ 1/(-2)3
= 1 โ 1 / [(-2)(-2)(-2)]
= 1 โ 1 / (-8)
= 1 โ (-1/8)
= -1/8
Example 7 :
Simplify :
5x-2
Solution :
= 5x-2
= 5/x2
Example 8 :
Simplify :
-4/k-4
Solution :
= -4/k-4
= -4 โ 1/k-4
= -4 โ k4
= -4k4
Example 9 :
Simplify :
a-3/x0b5
Solution :
= a-3/x0b5
= 1 / (a3 โ 1 โ b5)
= 1/a3b5
Example 10 :
Simplify :
2r0m-5
Solution :
= 2r0m-5
= 2 โ 1 โ 1/m5
= 2/m5
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