HOW TO FIND THE MISSING COORDINATES IF THREE POINTS LIE ON THE LINE

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Here we are going to see, how to find the missing coordinates if three points lie on the same line.

Slope :

If (x1,y1) and (x2,y2) are any two points on a line, with x1x2, then the slope of the line is

(y2 − y1) / (x2 − x1)

We will get the same slope for any two points lie on the same line.

Practice Questions

Question 1 :

Find a number t such that the point (−2, t) is on the line containing the points (5,−2) and (10,−8).

Answer :

Slope of the line passing through the points (-2, t) and (5, -2)  =  Slope of the line passing through the points (5, -2) and (10, -8).

Slope m  =  (y2 - y1)/ (x2 - x1)

(x1, y1)  ==>  (-2, t) and (x2, y2)  ==> (5, -2)  

m  =  (-2 - t)/(5 + 2)

m  =  (-2 - t)/7  ----(1)

(x1, y1)  ==>  (5, -2) and (x2, y2)  ==> (10, -8)  

m  =  (-8 + 2)/(10 - 5)

m  =  -6/5 ----(2)

-(2 + t)/7  =  -6/5

5(2 + t)  =  42

10 + 5t  =  42

5t  =  42 - 10

5t  =  32

t  =  32/5

Question 2 :

Find a number t such that the point (t, 2t) is on the line containing the points (3,−7) and (5,−15).

Answer :

Slope m  =  (y2 - y1)/ (x2 - x1)

(x1, y1)  ==>  (t, 2t) and (x2, y2)  ==> (3, -7)  

m  =  (-7 - 2t)/(3 - t) ---(1)

(x1, y1)  ==>  (3, -7) and (x2, y2)  ==> (5, -15)  

m  =  (-15 + 7)/(5 - 3)

m  =  -8/2

m  =  -4----(2)

(-7 - 2t)/(3 - t)  =  4

-7 - 2t  =  4(3 - t)

-7 - 2t  =  6 - 4t

-2t + 4t  =  6 + 7

2t  =  13

t  =  13/2

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