divisibility rule for 25

DIVISIBILITY RULE FOR 25

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In a number, if the last two digits are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.

Example :

Check whether 2800 is divisible by 25.

Solution :

According to the divisible rule of 25, if the last two digits of a number are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.

In the given number 2800, the last two digits are zeroes.

So, the number 2800 is divisible by 25.

Example 2 :

Check whether 1832 is divisible by 25.

Solution :

According to the divisible rule of 25, if the last two digits of a number are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.

In the given number 1832, the last two digits are not zeroes and also the number formed by the last two digits (32) is not a multiple of 25.

So, the number 1832 is not divisible by 25.

Example 3 :

Check whether 54875 is divisible by 25 or not.

Solution :

According to the divisible rule of 25, if the last two digits of a number are zeroes or the number formed by the last two digits is a multiple of 25, then the number is divisible by 25.

In the given number 54875, the number formed by the last two digits (75) is a multiple of 25.

So, the number 54875 is divisible by 25.

Example 4 :

Which of the following numbers should be multiplied by 20 to make a number divisible by 25 ?

(A) 2, (B) 3, (C) 5

Solution :

2 ⋅ 20 = 40

3 ⋅ 20 = 60

5 ⋅ 20 = 100

In the above calculation, when we multiply 5 by 20, we get 100 in which the last two digits are zeroes.

So, 100 is divisible by 25.

Therefore, option C is correct.