DERIVATIVE OF SQUARE ROOT OF COTX

We know the derivative of cscx, which is -cscxcotx.

(cotx)' = -csc²x

We can find the derivative of √cotx using chain rule.

If y = √cotx, find ᵈʸ⁄dₓ.

Let t = cotx.

Then, we have

y = √t

By chain rule,

Substitute t = cotx.

Therefore,

Kindly mail your feedback to v4formath@gmail.com

We always appreciate your feedback.