DERIVATIVE OF SQUARE ROOT OF COSX

We know the derivative of cosx, which is -sinx.

(cosx)' = -sinx

We can find the derivative of √cosx using chain rule.

If y = √cosx, find ᵈʸ⁄dₓ.

Let t = cosx.

Then, we have

y = √t

By chain rule,

Substitute t = cosx.

Therefore,

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