We know the derivative of lnx, which is ¹⁄ₓ. And also, the derivative sinx is cosx.
(lnx)' = ¹⁄ₓ
(sinx)' = cosx
We can find the derivative of ln(sinx) using chain rule.
If y = ln(sinx), find ᵈʸ⁄dₓ.
Let t = sinx.
Then, we have
y = lnt
By chain rule,
Substitute y = lnt and t = sinx.
Substitute t = sinx.
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