DERIVATIVE OF CSC SQUARE ROOT OF X

We know the derivative of cscx, which is -cscxsecx.

(cscx)' = -cscxsecx

We can find the derivative of csc(√x) using chain rule.

If y = csc(√x), find ᵈʸ⁄dₓ.

Let t = √x.

Then, we have

y = csct

By chain rule,

Substitute y = csct and t = √x.

Substitute t = √x.

Therefore,

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