We know the derivative of cscx, which is -cscxsecx.
(cscx)' = -cscxsecx
We can find the derivative of csc(√x) using chain rule.
If y = csc(√x), find ᵈʸ⁄dₓ.
Let t = √x.
Then, we have
y = csct
By chain rule,
Substitute y = csct and t = √x.
Substitute t = √x.
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