CO INTERIOR ANGLES PRACTICE WORKSHEET

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Find the values of the variables in the following :

Problem 1 :

cointerioranglesq1

Solution

Problem 2 :

cointerioranglesq2

Solution

Problem 3 :

cointerioranglesq3

Solution

Problem 4 :

cointerioranglesq4

Solution

Problem 5 :

cointerioranglesq5

Solution

Problem 6 :

cointerioranglesq6

Solution

Problem 7 :

cointerioranglesq7

Solution

Problem 8 :

a) Name a pair of complementary angles, a pair of supplementary angles, and a pair of adjacent angles.

b) Are ∠KGH and ∠LKG adjacent angles? Are ∠FGK and ∠FGH adjacent angles? Explain.

c) ∠1 is a complement of ∠2, and m∠2 = 5°. Find m∠1.

d) ∠3 is a supplement of ∠4, and m∠3 = 148°. Find m∠4.

alternate-interior-angles-q5

Solution

Problem 9 :

a. ∠1 is a complement of ∠2, and m∠1 = 62°. Find m∠2.

b. ∠3 is a supplement of ∠4, and m∠4 = 47°. Find m∠3.

Solution

Problem 10 :

What is the value of x?

alternate-interior-angles-q6

Solution

Problem 11 :

Find the values of x and y.

co-interior-angle-q1

Solution

Problem 12 :

Find FG and m∠G.

co-interior-angle-q2

Solution

Problem 13 :

Find the values of x and y.

co-interior-angle-q3

Solution

Problem 14 :

Find the values of x and y.

co-interior-angle-q4

Solution

Problem 15 :

You shoot a pool ball, and it rolls back to where it started, as shown in the diagram. The ball bounces off each wall at the same angle at which it hits the wall.

co-interior-angle-q5

a. The ball hits the first wall at an angle of 63°. So m∠AEF = m∠BEH = 63°. What is m∠AFE? Explain your reasoning.

b. Explain why m∠FGD = 63°.

c. What is m∠GHC? m∠EHB?

d. Is quadrilateral EFGH a parallelogram? Explain your reasoning.

Solution

Answer Key

1)  y = 53

2)  y = 110

3)  g = 123

4)  x = 108 and y = 108

5)  x = 3

6)  x = 6

7)  x= 5

8) 

a)

  • ∠LKG and  ∠FGK are complementary angles, because they add upto 90 degree.
  • ∠GKL and  ∠KGH are supplementary angles, because they add upto 180 degree.
  • ∠FGK and ∠KGH are adjacent angles.

b) 

  • ∠KGH and ∠LKG are not adjacent angles, because they are not next to each other.
  • ∠FGK and ∠FGH are not adjacent angles, because they are not next to each other.

c) m∠1 = 85

d) m∠4 = 32

9) a) m∠2 = 28

d) m∠4 = 133

10) x = 55.

11) x = 8 and y = 65

12) m∠G = 60 and FG = 8

13) x = 25 and y = 15

14) x = 32 and y = 29

15) 

a) m∠AFE = 27

b.  m∠FGD = 63° because the ball bounces at the same angle

c.  m∠GHC = 27  and m∠EHB = 27

d. Since opposite angles are equal, then it is parallelogram.

Problem 1 :

In the parallelogram shown below, find the value of x.

properties-of-parallelogram-q1

Solution

Problem 2 :

Quadrilateral RSTU is a parallelogram. Find the values of x, y, a, and b.

properties-of-parallelogram-q2

Solution

Problem 3 :

properties-of-parallelogram-q3

Solution

Problem 4 :

properties-of-parallelogram-q4

Solution

Problem 5 :

properties-of-parallelogram-q5

Solution

Problem 6 :

properties-of-parallelogram-q6

Solution

Problem 7 :

properties-of-parallelogram-q7

Solution

Problem 8 :

properties-of-parallelogram-q8

Solution

Problem 9 :

properties-of-parallelogram-q9

Solution

Problem 10 :

properties-of-parallelogram-q10

Solution

Problem 11 :

In the diagram of the parking lot shown, m∠JKL = 60°, JK = LM = 21 feet, and KL = JM = 9 feet.

co-interior-angle-q6

a) Explain how to show that parking space JKLM is a parallelogram.

b) Find m∠JML, m∠KJM, and m∠KLM.

c) LM || NO and NO || PQ . Which theorem could you use to show that JK II PQ ?.

Solution

Problem 12 :

Describe how to prove that ABCD is a parallelogram.

geo-properties-of-parallelgram-q1

Solution

Problem 13 :

Quadrilateral JKLM is a parallelogram. Describe how to prove that △MGJ ≅ △KHL.

geo-properties-of-parallelgram-q2

Solution

Problem 14 :

Three interior angle measures of a quadrilateral are 67°, 67°, and 113°. Is this enough information to conclude that the quadrilateral is a parallelogram? Explain your reasoning.

Solution

Answer Key

1) x = 4

2) b = 9 and a = 6

3) x = 100

4) x = 2 and y = 3

5) x = 5 and y = 6

6) x = 2

7) x = 2

8) x = 7

9) ∠F = 145

10) x = 5

11) 

a) Given that, JK = LM = 21 feet, and KL = JM = 9 feet

Since the opposite sides are equal, it must be a parallelogram.

b) m∠KLM = 120 (since opposite angles are equal)

c) LM || NO and NO || PQ

Using transitive property of parallel line, we say that JK II PQ.

12)

In triangle ADB and triangle DCB,

∠DAB = ∠DBC

AD = BC (opposite sides)

DE = DB (Common)

Triangle ABD and triangle BDC are congruent. 

Using CPCTC, AB = DC

13) SAS, then △MGJ ≅ △KHL.

14) Since the opposite angles are equal, then it is parallelogram.

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