addition practice worksheets

Addition Practice Worksheets

Problem 1 :

Mohan has 376 oranges. Tina has 828 more oranges than Mohan. How many oranges does Tina have?

Solution :

Number of oranges Mohan has = 376

Number of oranges Tina has = 376 + 828

= 1204

Number of oranges Tina has is 1204.

Problem 2 :

Rina has 819 apples. Ram has 618 less apples than Rina. How many more apples Rina has?

Solution :

Number of apples Rina has = 819

Number of apples Ram has = 819 - 618

= 201

Problem 3 :

Westview School is buying 12 new basketball uniforms. Each uniform costs $46. Which equation shows a way to find the total cost of the uniforms?

A) (40 × 10) + (6 × 2) = 400 + 12

B) (40 × 6) + (10 × 2) = 240 + 20

C) (40 × 12) + (6 × 12) = 480 + 72

D) (40 × 12) + (60 × 12) = 480 + 720

E) None of the above

Solution :

Number of basket ball uniforms purchased = 12

Cost of each = $46

Total cost = 12 x 46

Decomposing it, we get

12 = 10 + 2

46 = 40 + 6

46 x 12 = (40 + 6) x 12

Using distributive property,

= 40 x 12 + 6 x 12

= 480 + 72

So, option C is correct.

Problem 4 :

For three days, Kitty was catching mice. Each day Kitty caught 2 more mice than she did the previous day. In total, how many mice did Kitty catch during these three days?

A. 14 B. 13 C. 8 D. 10 E. 9

Solution :

Number of mice cought by Kitty on the first day = 1

Number of mice cought by kitty in the second day = 1 + 2

= 3

Number of mice cought by kitty in the third day = 3 + 2

= 5

Total number of kitty's = 1 + 3 + 5

= 9

So, option E is correct.

Problem 5 :

Laura decorated each of her 24 cookies. She decorated 15 cookies with green colour and 13 cookies with blue colour. How many cookies were decorated with both green and blue colour?

A. 4 B. 3 C. 5 D. 6 E. 2

Solution :

Number of cookies she has = 24

Number of cookies decorated with green color = 15

Number of cookies decorated with blue color = 13

Number of cookies decorated with both colors = 15 + 13

= 28 - 24

= 4

So, option A is correct.

Problem 6 :

The sum of ages of Allie, Diana and Zoe is 15. Next year, the sum of their ages will be ____.

A. 16 B. 18 C. 17 D. 15 E. 45

Solution :

Let A, D and Z be the ages of Allie's, Diana's and Zoe's present ages.

Next year, each of them ages will be added with 1.

Sum of ages of these persons = 15 + (1 + 1 + 1)

= 18

So, option B is correct.

Problem 7 :

Hailey wrote a one-digit number, then she wrote another digit to its right. She added 27 to the obtained number and got 91. What was the first digit that she wrote?

A. 4 B. 6 C. 5 D. 7 E. 8

Solution :

Let xy be the two digit number.

xy + 27 = 91

10x + y + 27 = 91

10x + y = 91 - 27

10x + y = 64

Let x be applies as 4,

When y = 64 - 40 ==> 24. So, it is not correct,
When y = 64 - 60 ==> 4. So, it is correct.

So, option B is correct.

Problem 8 :

Cindy saved $15 in the first month, $30 in the second month, $45 in the third month, and so forth. The amount of money she saved in the last month was $120. How much money did Cindy save in total?

A. 210 B. 300 C. 350 D. 420 E. 540

Solution :

Amount saved by Cindy in the first month = $15

Second month savings = $30

Third months savings = $45

15, 30, 45, 60, 75, 90, 105, 120

Total savings = 15 + 30 + 45 + 60 + 75 + 90 + 105 + 120

= 540

So, option E is correct.

Problem 9 :

Hannah went to the shop. She bought a magazine that cost $3.50, 3 bars of chocolate that cost 55 cents each and a packet of sweets. She paid with a $10 note and was given $4.20 change. How much did the sweets cost?

Solution :

Cost of magazine = $3.50

Cost of 1 chocolate = $0.55

Cost of 3 chocolate bars = 3(0.55)

= 1.65

Amount he spent in the shop = 10 - 4.20

= 5.80

Cost of magazine + cost of 3 chocolate bars + packet of sweet = 5.80

3.50 + 1.65 + cost of packet of sweet = 5.80

5.15 + cost of packet of sweet = 5.80

Cost of packet of sweet = 5.80 - 5.15

= 0.65