USING PROPERTIES OF KITES WORKSHEET

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Find the measures of the numbered angles in each kite.

Problem 1 :

Problem 2 :

Problem 3 :

Problem 4 :

Problem 5 :

Problem 6 :

Problem 7 :

Problem 8 :

Problem 9 :

Problem 10 :

Given WXYZ is a kite, m∠YWX = 2x + 30, and m∠WYX = 4x. Find m∠YWX.

Solution

Answer Key

∠1 = 90^º

∠DAO = 68^º

∠1 = ∠COD = 90^º

∠2 = ∠ODC

∠3 = ∠OCD = 45^º

∠ODC = 45^º

3) m ∠A = m ∠C = 108^º

4) ∠CDO = 26^º, ∠OCB = 64º

5) ∠OAB = 40^º, ∠COB = ∠COD = 90^º

6) ∠COB = ∠AOB = 90^º, ∠2 = ∠OCB = 55º, ∠4 = ∠OAB = 55^º, ∠5 = ∠OBA = 35^º

7) ∠1 = 90^º, ∠OCB = 52^º, ∠OCD = 37^º, ∠OCB = 52^º, ∠5 = ∠CDO = 53^º

8) ∠1 = ∠2 = ∠3 = ∠4 = 90, ∠7 = ∠OAB = 56, ∠8 = ∠OAD = 44, ∠9 = ∠OCB = 56

∠10 = ∠OCD = 44

9) m ∠A = m ∠C = 112^º

10) x = 15

Problem 1 :

The area of this shape is 48 ft². Solve for x.

Solution

Problem 2 :

The area of this shape is 32 in². Solve for x.

Solution

Problem 3 :

Find the area of the kite given below,

Solution

Problem 4 :

Draw a kite with diagonals of 20 and 24. What is the area of the kite?

Solution

Problem 5 :

In the kite WXYZ, find length of all sides.

Solution

Problem 6 :

In the kite ABCD, AB = 6 cm, CD = 9 cm and AC = 12 cm.

Solution

Problem 7 :

Given kite ADEC, CB = 3x + 6, BD = 8x - 9, AB = 7x - 1. Find AB.

Solution

Problem 8 :

Find AB

Given that kite ABCE, find X and Y.

Solution

Problem 9 :

Given that kite ABCD, find x.

Solution

Problem 10 :

Given that kite ABCD, find ∠ABC, ∠CED and ∠CEB.

Solution

Problem 11 :

Solution

Answer Key

1) x = 12

2) x = 2

3) area of a kite is 100.

4) area of a kite is 240.

5) WX = √74 and WZ = √74

6) x = 4.35

7) x = 3, AB = 20

8) X = 40 and Y = 50

9) x = 12

10) ∠CEB = 90

11) the values of x and y are 6 and 4 respectively.

Find the area of each kite.

Problem 1 :

Solution

Problem 2 :

Solution

Problem 3 :

Solution

Problem 4 :

The area of a kite is 120 cm². The length of one diagonal is 20 cm. what is the length of the other diagonal?

a) 12cm b) 20 cm c) 24 cm d) 48 cm

Solution

Problem 5 :

A kite has vertices at the points (2, 0) (3, 2) (4, 0) and (3, -3). Find the perimeter and area of the kite.

Solution

Problem 6 :

The area of a kite is 324 square inches. One diagonal is twice as long as the other diagonal. Find the length of each diagonal.

Solution

Problem 7 :

The vertices of the quadrilateral are A(2, 8), B (7, 9), C(11, 2) and D(3, 3). Show that ABCD is a kite and find the area of the kite.

Solution

Problem 8 :

You and a friend are building a kite. You need a stick to place from X to W and a stick to place from W to Z to finish constructing the frame. You want the kite to have the geometric shape of a kite. How long does each stick need to be? Explain your reasoning

Solution

Answer Key

1) area of a kite is 80 in².

2) area of a kite is 18 m².

3) area of a kite is 24 ft².

4) length of the other diagonal is12 cm.

5) perimeter of the kite is 10.78 units.

6) the lengths of diagonals are 18 inches and 36 inches.

7) Area of kite = 39 square units

Perimeter of kite = = 26.3 units.

8) Since it is kite, pair of sides will be equal.

Find the length of the missing diagonal in each kite.

Problem 1 :

Find HF if GE = 43 yd.

Solution

Problem 2 :

Find NL if MK = 18 in.

Solution

Problem 3 :

Find BD if AC = 47 yd.

Solution

Problem 4 :

Find TV if SU = 30 ft.

Solution

Problem 5 :

Find EG if DF = 15 ft.

Solution

Problem 6 :

Find XZ if WY = 32 in.

Solution

Problem 7 :

Find QS if PR = 11 yd.

Solution

Problem 8 :

The area of rhombus 90 square units. If one diagonal is 10 units, find the length of the other diagonal.

Solution

Problem 9 :

The rhombus has perimeter of 100 meters and a diagonal 30 meters long. Find the area of the rhombus.

Solution

Problem 10 :

The rhombus has an area of 20 and one diagonal of length 12. Find the length of the other diagonal.

Solution

Problem 11 :

The length of one of its diagonals of a kite is 4 cm longer than twice the length of the other diagonal. The area of the kite is 15 cm². Find the length of the other diagonal.

Solution