To know the shortcuts required to solve problems on time, speed and distance,

**Problem 1 :**

If a person drives his car in the speed 50 miles per hour, how far can he cover in 2.5 hours ?

**Solution :**

**Given :** Speed is 50 miles per hour.

So, the distance covered in 1 hour is

= 50 miles

Then, the distance covered in 2.5 hours is

= 2.5 ⋅ 50 miles

= 125 miles

So, the person can cover 125 miles of distance in 2.5 hours.

**Problem 2 : **

If a person travels at a speed of 40 miles per hour. At the same rate, how long will he take to cover 160 miles distance ?

**Solution :**

**Given :** Speed is 40 miles per hour.

The formula to find the time when distance and speed are given is

Time = Distance / Speed

Time taken to cover the distance of 160 miles is

Time = 160 / 40

Time = 4 hours

So, the person will take 4 hours to cover 160 miles distance at the rate of 40 miles per hour.

**Problem 3 : **

A person travels at a speed of 60 miles per hour. How far will he travel in 4.5 hours ?

**Solution :**

**Given :** Speed is 60 miles per hour.

The distance covered in 1 hour is

= 60 miles

Then, the distance covered in 4.5 hours is

= 4.5 ⋅ 60 miles

= 270 miles

So, the person will travel 270 miles distance in 4.5 hours.

**Problem 4 :**

A person travels at a speed of 60 kms per hour. Then how many meters can he travel in 5 minutes ?

**Solution :**

**Given :** Speed is 60 kms per hour.

The distance covered in 1 hour or 60 minutes is

= 60 kms

= 60 ⋅ 1000 meters

= 60000 meters

Then the distance covered in 1 minute is

= 60000/60

= 1000 m

The distance covered in 5 minutes is

= 5 ⋅ 1000

= 5000 meters

So, the person can cover 5000 meters distance in 5 minutes.

**Problem 5 : **

A person covers 108 kms in 3 hours. What is his speed in meter per second ?

**Solution :**

**Given :** Distance is 108 kms and time is 3 hours.

The given distance in meters :

= 108 ⋅ 1000

= 108,000 meters

The given time in seconds :

= 3 ⋅ 60 minutes

= 180 minutes

= 180 ⋅ 60 seconds

= 10,800 seconds

The formula to find the speed is

Speed = Distance / Time

Speed in meter per second is

= 108,000 / 10,800

= 10 m/sec

So, his speed in meter per second is 10.

**Problem 6 : **

A person covers 90 kms in 2 hours 30 minutes. Find the speed in meter per second.

**Solution :**

**Given :** Distance is 90 kms and time is 2 hrs 30 min.

The given distance in meters :

= 90 ⋅ 1000

= 90,000 meters

The given time in seconds :

= 2 hrs 30 min

= (120 + 30) min

= 150 minutes

= 150 ⋅ 60 seconds

= 9,000 seconds

The formula to find the speed is

Speed = Distance / Time

Speed in meter per second is

= 90,000 / 9,000

= 10 m/sec

So, his speed in meter per second is 10.

**Problem 7 : **

A person travels at the rate of 60 miles per hour and covers 300 miles in 5 hours. If he reduces his speed by 10 miles per hour, how long will he take to cover the same distance ?

**Solution :**

Original speed is 60 miles per hour.

If the speed is reduced by 10 miles per hour, then the new speed is

= 50 miles per hour

Distance to be covered is 300 miles.

The formula to find time is

Time = Distance / Speed

Time taken to cover 300 miles distance at the speed of 50 miles per hour is

= 300 / 50

= 6 hours

So, if the person reduces his speed by 10 miles per hour, he will take 6 hours to cover 300 miles distance.

**Problem 8 : **

A person travels 50 kms per hour. If he increases his speed by 10 kms per hour, how many minutes will he take to cover 8000 meters ?

**Solution :**

Original speed is 50 kms per hour.

If the speed is increased by 10 kms per hour, then the new speed is

= 60 kms per hour

Because, we have to find the time in minutes for the distance given in meters, let us change the speed from kms per hour into meters per minute.

1 hour ------> 60 kms

1 ⋅ 60 minutes ------> 60 ⋅ 1000 meters

60 minutes ------> 60,000 meters

1 minute ------> 60,000 / 60 meters

1 minute ------> 1000 meters

So, the speed is 1000 meters/minute.

The formula to find time is

Time = Distance / Speed

Time taken to cover 8000 meters distance at the speed of 1000 meters per minute is

= 8000 / 1000

= 8 minutes

So, if the person increases his speed by 10 kms per hour, he will take 8 minutes to cover 8000 meters distance.

**Problem 9 : **

A person can travel at the speed of 40 miles per hour. If the speed is increased by 50%, how long will it take to cover 330 miles ?

**Solution :**

Original speed is 40 miles per hour

If the speed is increased by 50%, then the new speed is

= 150 % of 40

= 1.5 ⋅ 40

= 60 miles per hour

Distance to be covered is 330 miles.

The formula to find time is

Time = Distance / Speed

Time taken to cover 330 miles distance at the speed of 60 miles per hour is

= 330 / 60

= 5.5 hours

= 5 hrs 30 minutes

So, if the person is increased by 50%, it will take 5 hrs 30 minutes to cover 330 miles distance.

**Problem 10 : **

A person speed at a rate of 40 kms per hour. If he increases his speed by 20%, what is his new speed in meter per minute ?

**Solution :**

Original speed is 40 kms per hour

If the speed is increased by 20%, then the new speed is

= 120 % of 40

= 1.2 ⋅ 40

= 48 kms per hour

Now, let us change the speed from kms per hour into meters per minute.

1 hour ------> 48 kms

1 ⋅ 60 minutes ------> 48 ⋅ 1000 meters

60 minutes ------> 48,000 meters

1 minute ------> 48,000 / 60 meters

1 minute ------> 800 meters

So, the speed is 800 meters/minute.

If the person increases his speed by 20%, his new speed will be 800 meter per minute.

Apart from the stuff given above, if you need any other stuff in math, please use our google custom search here.

If you have any feedback about our math content, please mail us :

**v4formath@gmail.com**

We always appreciate your feedback.

You can also visit the following web pages on different stuff in math.

**WORD PROBLEMS**

**Word problems on simple equations **

**Word problems on linear equations **

**Word problems on quadratic equations**

**Area and perimeter word problems**

**Word problems on direct variation and inverse variation **

**Word problems on comparing rates**

**Converting customary units word problems **

**Converting metric units word problems**

**Word problems on simple interest**

**Word problems on compound interest**

**Word problems on types of angles **

**Complementary and supplementary angles word problems**

**Trigonometry word problems**

**Markup and markdown word problems **

**Word problems on mixed fractrions**

**One step equation word problems**

**Linear inequalities word problems**

**Ratio and proportion word problems**

**Word problems on sets and venn diagrams**

**Pythagorean theorem word problems**

**Percent of a number word problems**

**Word problems on constant speed**

**Word problems on average speed **

**Word problems on sum of the angles of a triangle is 180 degree**

**OTHER TOPICS **

**Time, speed and distance shortcuts**

**Ratio and proportion shortcuts**

**Domain and range of rational functions**

**Domain and range of rational functions with holes**

**Graphing rational functions with holes**

**Converting repeating decimals in to fractions**

**Decimal representation of rational numbers**

**Finding square root using long division**

**L.C.M method to solve time and work problems**

**Translating the word problems in to algebraic expressions**

**Remainder when 2 power 256 is divided by 17**

**Remainder when 17 power 23 is divided by 16**

**Sum of all three digit numbers divisible by 6**

**Sum of all three digit numbers divisible by 7**

**Sum of all three digit numbers divisible by 8**

**Sum of all three digit numbers formed using 1, 3, 4**

**Sum of all three four digit numbers formed with non zero digits**