Problem 1 :
Mrs. Farrell’s class has 26 students. Only 21 were present on Monday. How many were absent ?
To find the number of students absent, subtract 21 from 26.
= 26 - 21
So, there were 5 students absent on Monday.
Problem 2 :
There were 1028 books in the library today. If 76 books were bought yesterday, how many books were in the library day before yesterday ?
To find the number of books in the library day before yesterday, subtract 76 from 1028.
= 1028 - 76
So, there were 952 books in the library day before yesterday.
Problem 3 :
In an art competition, 1837 students took part. If 781 among them were boys, how many girls did take part in the competition ?
To find the number of girls, subtract 781 from 1837.
= 1837 - 781
So, 1056 girls took part in the competition.
Problem 4 :
The temperature at 6 P.M. was 31°F. By midnight, it had dropped 40°F. What was the temperature at midnight ?
Visualize a number line. The drop from 31° to 0° is 31°. There are still 9 more degrees to drop. They will be below zero. -9°F is the temperature at midnight.
Problem 5 :
In an Examination, Jack scored 632 marks and received grade A, William scored 75 marks less than Jack and received grade B. Find the marks scored score William.
To find the marks scored by William, subtract 75 from 632.
= 632 - 75
So, William scored 557 marks.
Problem 6 :
Jack sold 1257 meatballs on Sunday. He sold 158 less more meatballs on Monday than on Saturday. How many meatballs did he sell on Monday ?
Number of meatballs sold on Sunday :
Given : On Monday, 158 less meatballs sold than on Sunday.
Then, number of meatballs sold on Monday :
= 1257 - 158
So, Jack sold 1099 meatballs on Monday.
Problem 7 :
Distance from place A to C is 183 miles, distance from place B to place C is two-third of the distance from place A to place C. If B is between A and C, find the distance from place A to place B.
Distance from place A to place C :
= 183 miles
Distance from place B to place C :
= 2/3 ⋅ (Distance from A to C)
= 2/3 ⋅ 183 miles
= 122 miles
Distance from place A to place B :
= (Distance from A to C) - (Distance from B to C)
= 183 - 122
= 61 miles
So, the distance from Place A to place B is 61 miles.
Problem 8 :
In a running race, Michael reached the target in 2 minutes 5 seconds and lost the first price by 12 seconds. In what time should he have completed the race to get the first price ?
Actual time taken by Michael to complete the race :
= 2 min 5 sec
= 120 sec + 5 sec
= 125 seconds
Given : Michael lost the first price by 12 seconds.
Then, to find the time required to get the first price, subtract 12 from 125.
= 125 - 12
= 113 seconds
So, Michael should have completed the race in 113 seconds to get the first price.
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