**Problem
1 : **

Mrs. Farrell’s class has 26 students. Only 21 were present on Monday. How many were absent ?

**Solution : **

To find the number of students absent, subtract 21 from 26.

= 26 - 21

= 5

So, there were 5 students absent on Monday.

**Problem 2 : **

There were 1028 books in the library today. If 76 books were bought yesterday, how many books were in the library day before yesterday ?

**Solution : **

To find the number of books in the library day before yesterday, subtract 76 from 1028.

= 1028 - 76

= 952

So, there were 952 books in the library day before yesterday.

**Problem 3 : **

In an art competition, 1837 students took part. If 781 among them were boys, how many girls did take part in the competition ?

**Solution : **

To find the number of girls, subtract 781 from 1837.

= 1837 - 781

= 1056

So, 1056 girls took part in the competition.

**Problem 4 : **

The temperature at 6 P.M. was 31°F. By midnight, it had dropped 40°F. What was the temperature at midnight ?

**Solution : **

Visualize a number line. The drop from 31° to 0° is 31°. There are still 9 more degrees to drop. They will be below zero. -9°F is the temperature at midnight.

**Problem 5 : **

In an Examination, Jack scored 632 marks and received grade A, William scored 75 marks less than Jack and received grade B. Find the marks scored score William.

**Solution : **

To find the marks scored by William, subtract 75 from 632.

= 632 - 75

= 557

So, William scored 557 marks.

**Problem 6 : **

Jack sold 1257 meatballs on Sunday. He sold 158 less more meatballs on Monday than on Saturday. How many meatballs did he sell on Monday ?

**Solution : **

Number of meatballs sold on Sunday :

= 1257

Given : On Monday, 158 less meatballs sold than on Sunday.

Then, number of meatballs sold on Monday :

= 1257 - 158

= 1099

So, Jack sold 1099 meatballs on Monday.

**Problem 7 : **

Distance from place A to C is 183 miles, distance from place B to place C is two-third of the distance from place A to place C. If B is between A and C, find the distance from place A to place B.

**Solution : **

Distance from place A to place C :

= 183 miles

Distance from place B to place C :

= 2/3 ⋅ (Distance from A to C)

= 2/3 ⋅ 183 miles

= 122 miles

Distance from place A to place B :

= (Distance from A to C) - (Distance from B to C)

= 183 - 122

= 61 miles

So, the distance from Place A to place B is 61 miles.

**Problem 8 : **

In a running race, Michael reached the target in 2 minutes 5 seconds and lost the first price by 12 seconds. In what time should he have completed the race to get the first price ?

**Solution : **

Actual time taken by Michael to complete the race :

= 2 min 5 sec

= 120 sec + 5 sec

= 125 seconds

Given : Michael lost the first price by 12 seconds.

Then, to find the time required to get the first price, subtract 12 from 125.

= 125 - 12

= 113 seconds

So, Michael should have completed the race in 113 seconds to get the first price.

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