Problem 1 :
Mrs. Farrell’s class has 26 students. Only 21 were present on Monday. How many were absent ?
Solution :
To find the number of students absent, subtract 21 from 26.
= 26 - 21
= 5
So, there were 5 students absent on Monday.
Problem 2 :
There were 1028 books in the library today. If 76 books were bought yesterday, how many books were in the library day before yesterday ?
Solution :
To find the number of books in the library day before yesterday, subtract 76 from 1028.
= 1028 - 76
= 952
So, there were 952 books in the library day before yesterday.
Problem 3 :
In an art competition, 1837 students took part. If 781 among them were boys, how many girls did take part in the competition ?
Solution :
To find the number of girls, subtract 781 from 1837.
= 1837 - 781
= 1056
So, 1056 girls took part in the competition.
Problem 4 :
The temperature at 6 P.M. was 31°F. By midnight, it had dropped 40°F. What was the temperature at midnight ?
Solution :
Visualize a number line. The drop from 31° to 0° is 31°. There are still 9 more degrees to drop. They will be below zero. -9°F is the temperature at midnight.
Problem 5 :
In an Examination, Jack scored 632 marks and received grade A, William scored 75 marks less than Jack and received grade B. Find the marks scored score William.
Solution :
To find the marks scored by William, subtract 75 from 632.
= 632 - 75
= 557
So, William scored 557 marks.
Problem 6 :
Jack sold 1257 meatballs on Sunday. He sold 158 less meatballs on Monday than on Saturday. How many meatballs did he sell on Monday ?
Solution :
Number of meatballs sold on Sunday :
= 1257
Given : On Monday, 158 less meatballs sold than on Sunday.
Then, number of meatballs sold on Monday :
= 1257 - 158
= 1099
So, Jack sold 1099 meatballs on Monday.
Problem 7 :
Distance from place A to C is 183 miles, distance from place B to place C is two-third of the distance from place A to place C. If B is between A and C, find the distance from place A to place B.
Solution :
Distance from place A to place C :
= 183 miles
Distance from place B to place C :
= 2/3 ⋅ (Distance from A to C)
= 2/3 ⋅ 183 miles
= 122 miles
Distance from place A to place B :
= (Distance from A to C) - (Distance from B to C)
= 183 - 122
= 61 miles
So, the distance from Place A to place B is 61 miles.
Problem 8 :
In a running race, Michael reached the target in 2 minutes 5 seconds and lost the first price by 12 seconds. In what time should he have completed the race to get the first price ?
Solution :
Actual time taken by Michael to complete the race :
= 2 min 5 sec
= 120 sec + 5 sec
= 125 seconds
Given : Michael lost the first price by 12 seconds.
Then, to find the time required to get the first price, subtract 12 from 125.
= 125 - 12
= 113 seconds
So, Michael should have completed the race in 113 seconds to get the first price.
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