**Problem 1 :**

Subbu spends 1/3 of his monthly earnings on rent, 2/5 on food and 1/10 on monthly usuals. What fractional part of his earnings is left with him for other expenses?

**Solution :**

Amount spent for rent = 1/3

Amount spent for food = 2/5

Amount spent for monthly usual = 1/10

Required amount left over = 1 - [(1/3) + (2/5) + (1/10)]

L.C.M (3, 5, 10) = 30

= 1 - [(10+12+3)/30]

= 1 - (25/30)

= (30-25)/30

= 5/30

= 1/6

**Problem 2 :**

In a constituency, 19/25 of the voters had voted for candidate A whereas 7/50 had voted for candidate B. Find the rational number of the voters who had voted for others.

**Solution :**

Part of voters had voted for candidate A = 19/25

Part of voters had voted for candidate B = 7/50

Part of voters voted for others = 1 - [(19/25) + (7/50)]

L.C. M (25, 50) = 50

= 1 - [(38 + 7)/50]

= 1 - (45/50)

= (50-45)/50

= 5/50

= 1/10

**Problem 3 :**

If 3/4 of a box of apples weighs 3 kg and 225 gm, how much does a full box of apples weigh?

**Solution :**

1 kg = 1000 g

3 kg = 3000

Therefore, 3000g + 225g = 3225 g

Finding the weight :-

3/4 of box weighs = 3225g

1/4 of box weighs = 3225/3 = 1075

Weight of box = 3225 + 1075 = 4300

Hence, required answer is 4 kg 300 g

**Problem 4 :**

Mangalam buys a water jug of capacity 3 4/5 litres. If she buys another jug which is 2 2/3 times as large as the smaller jug, how many litres can the larger one hold?

**Solution :**

Capacity of jug = 3 4/5 liters = 19/5

Now the volume of the second jug = 2 2/3 times of the first jug

= 8/3

So, the volume or capacity of the second jug( larger jug)

= (19/5) ⋅ (8/3)

= 152/15

= 10 2/5 liters

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