# SOLVING SIMPLE EQUATIONS WORD PROBLEMS (Part - 1)

Problem 1 :

18 is taken away from 8 times of a number is 30. Find the number.

Solution :

Problem 2 :

If the average of three consecutive odd numbers is 13, find the numbers.

Solution :

Problem 3 :

The denominator of a fraction exceeds the numerator by 5. If 3 be added to both, the fraction becomes ¾. Find the fraction.

Solution :

Problem 4 :

If thrice of A's age 6 years ago be subtracted from twice his present age, the result would be equal to his present age. Find A's present age.

Solution :

Problem 5 :

A number consists of two digits. The digit in tens place is twice the digit in ones place. If 18 be subtracted from the number, the digits are reversed. Find the number.

Solution :

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