SOLVING LITERAL EQUATIONS WORKSHEET

Problem 1 :

Solve for w in the formula for area of a rectangle : 

A  =  l ⋅ w

Problem 2 :

Solve for c in the formula for Einstein’s Theory of Relativity : 

E  =  mc2

Problem 3 :

Solve for h in the formula for the surface area of a right cylinder :

S  =  2∏r(h + r)

Problem 4 : 

Solve for r in the formula for volume of sphere :

V  =  4/3 ⋅ ∏r3

Problem 5 :

Solve for w in the formula for perimeter of the rectangle :

P  =  2(l + w)

Problem 6 :

Solve for a :

Q  =  3a + 5ac

Problem 7 : 

Solve for b1 :

A  =  1/2 ⋅ h(b1 + b2)

Problem 8 : 

Solve for b :

a2 + b2  =  c2

Detailed Answer Key

Problem 1 :

Solve for w in the formula for area of a rectangle : 

A  =  l ⋅ w

Solution : 

A  =  l ⋅ w

Divide each side by l.

A / l  =  w

Problem 2 :

Solve for c in the formula for Einstein’s Theory of Relativity : 

E  =  mc2

Solution : 

E  =  mc2

Divide each side by m.

E / m  =  c2

Take square root on each side. 

√(E/m)  =  √c2

√(E/m)  =  c

Problem 3 : 

Solve for h in the formula for the surface area of a right cylinder :

S  =  2πr(h + r)

Solution : 

S  =  2πr(h + r)

Use distributive property of multiplication over addition. 

S  =  2πrh + 2πr2

Subtract 2∏rfrom each side. 

S - 2πr =  2πrh

Divide each side by 2∏r. 

(S - 2πr2) / 2πr  =  h

Problem 4 : 

Solve for r in the formula for volume of sphere :

V  =  4/3 ⋅ πr3

Solution : 

V  =  4/3 ⋅ πr3

Multiply each side by 3/4. 

3V/4  =  πr3

Divide each side by ∏.

3V/4π  =  r3

Take cube root on each side. 

3√(3V/4π)  =  3√r3

3√(3V/4π)  =  r

Problem 5 :

Solve for w in the formula for perimeter of the rectangle :

P  =  2(l + w)

Solution : 

P  =  2(l + w)

Use distributive property of multiplication over addition. 

P  =  2l + 2w

Subtract 2l from each side. 

P - 2l  =  2w

Divide each side by 2. 

(P - 2l) / 2  =  w

Problem 6 :

Solve for a :

Q  =  3a + 5ac

Solution : 

Q  =  3a + 5ac

Factor a out of 3a + 5ac. 

Q  =  a(3 + 5c)

Divide each side by (3 + 5c). 

Q / (3 + 5c)  =  a

Problem 7 : 

Solve for b1 :

A  =  1/2 ⋅ h(b1 + b2)

Solution : 

A  =  1/2 ⋅ h(b1 + b2)

Multiply each side by 2/h. 

2A/h  =  b1 + b2

Subtract b2 from each side. 

2A/h - b2  =  b1

Problem 8 : 

Solve for b :

a2 + b2  =  c2

Solution : 

a2 + b2  =  c2

Subtract a2 from each side. 

b2  =  c- a2

Take square root on each side. 

b2  =  √(c- a2)

b  =  √(c- a2)

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