In this section, you will learn how to find slope of a line passing through the midpoint of the line segment.
Example 1 :
Find the slope of the line which passes through the origin and the midpoint of the line segment joining the points (0 ,- 4) and (8 , 0).
Midpoint of the line segment = (x1 + x2)/2, (y1 + y2)/2
= (0 + 8)/2, (-4 + 0)/2
= (8/2, -4/2)
= (4, -2)
Slope of the passing through the point (4, -2) and (0, 0) is
m = (y2 - y1)/(x2 - x1)
m = (0 + 2)/(0 - 4)
m = -2/4 = -1/2
Example 2 :
The side AB of a square ABCD is parallel to x-axis . Find the
(i) slope of AB (ii) slope of BC (iii) slope of the diagonal AC
(i) Slope of AB
The side AB is parallel to x-axis, hence the slope of AB is 0.
(ii) slope of BC
The side BC is perpendicular to x-axis, hence its slope is undefined.
(iii) slope of the diagonal AC
Angle of inclination of the diagonal AC is 45
m = tan 45
m = 1
Example 3 :
The side BC of an equilateral Δ ABC is parallel to x-axis. Find the slope of AB and the slope of BC
The side BC is parallel to x-axis, hence its slope is undefined.
Since it is right triangle the angle of inclination is 60
m = tan 60
m = √3
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