PROBLEMS ON PROPERTIES OF SQUARE

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What is square ?

A square is a rhombus with four equal angles of 90.

squareonquad

Properties :

  • Opposite sides are parallel.
  • All sides are equal in length.
  • Diagonals bisect each other at right angles.
  • Diagonals bisect the angles at each vertex.
  • Diagonals are equal in length.

Problem 1 :

The square ABCD, find each length or angle measure.

propertiesofsquareq1

1)  BX

2)  AX

3)  DB

4)  AC

5)  AB

6)  BC

7)  ∠AXB

8)  ∠XAB

Solution :

1)  In square, the diagonal will bisect each other. So, BX = 8.5

2)  Diagonals are equal, AX = 8.5

3)  DB = 2DX, DB = 2(8.5)  ==>  17

4)  Diagonals are equal. So AC = 17

5)  AB = 19

6)  BC = 19

7)  Diagonals will bisect each other at right angle, ∠AXB = 90

8)  Diagonals will bisect the vertex angle, ∠XAB = 45

Problem 2 :

Classify the special quadrilateral. Then find the values of x and y. 

propertiesofsquareq2

Solution :

Since all sides are equal and angles at vertex is 90 degree. The given shape is square.

AB = DC

5x - 4 = 2y + 4

5x - 2y = 4 + 4

5x - 2y = 8 ------(1)

AD = BC

5y + 1 = 3x

3x - 5y = 1

3x - 5y = 1 ------(2)

(1) ⋅ 5 ==> 25x - 10y = 40

(2) ⋅ 2 ==> 6x - 10y = 2

(1) - (2)

19x = 38

x = 38/19

x = 2

By applying x = 1 in (1), we get

5(2) - 2y = 8

10 - 2y = 8

-2y = 8 - 10

-2y = -2

y = 1

Problem 3 :

For the square ABCD, find the missing values.

propertiesofsquareq3

1) x

2) y

3) AD

4) DB

Solution :

Diagonals will bisect each other.

18 = 2x + 2y

Dividing by 2 on both sides.

9 = x + y

x + y = 9 ----(1)

All sides will be equal.

AB = AD

30 = 2x + 5y

2x + 5y = 30 ----(2)

(1) ⋅ 2 - (2) ==> (2x + 2y) - (2x + 5y) = 9 - 30

2y - 5y = -21

-3y = -21

y = 7

Applying the value of y in (1), we get x = 9 - 7

x = 2

AD = 2x + 5y

= 2(2) + 5(7)

= 4 + 35

AD = 39

DB = 18 + 2x + 2y

= 18 + 2(2) + 2(7)

= 18 + 4 + 14

DB = 36

Problem 4 :

The diagonals of square DEFG intersect at H. Given that EH = 5, find the indicated measure. 

propertiesofsquareq4

1)  ∠GHF

2)  HF

3)  ∠DGH

4)  DE

Solution :

1)  ∠GHF = 90 degree

2)  HF = 5

3)  ∠DGH = 45 degree

4)  In triangle DHE,

(DE)2 = DH2 + HE2

DE2 = 52 + 52

DE2 = 25 + 25

DE = √50

DE = 5√2

Problem 5 :

ABCD is a given rectangle with length as 80 cm and breadth as 60 cm. P, Q, R, S are the mid points of sides AB, BC, CD, DA respectively. A circular rangoli of radius 10 cm is drawn at the center as shown in figure given below. Find the area of shaded portion.

propertiesofsquareq5

Solution :

DC = 80 cm, DR = 40 cm

DA = 60 cm, DS = 30 cm

In triangle DRS,

RS2 = DR2 + DS2

RS2 = 402 + 302

RS2 = 1600 + 900

RS2 = 2500

RS = 50

RS = PQ = SP = RQ

Area of square PQRS = 2500

Area of circleπr2

radius = 5 cm

= 3.14 (5)2

= 3.14(25)

= 78.5

Area of shaded portion = 2500 - 78.5

= 1921.5 cm2

Problem 6 :

A large square is made by arranging a small square surrounded by four congruent rectangles as shown in figure given below. If the perimeter of each of the rectangle is 16 cm, find the area of the large square.

propertiesofsquareq6

Solution :

propertiesofsquaresol6

Perimeter of the rectangle = 16 inches

2(l + b) = 16

l + b = 8

Side length of the square = l + b

Area of square = (l + b)2

= 82

= 64

Problem 7 :

ABCD is a square with AB = 15 cm. Find the area of the square BDFE. 

propertiesofsquareq7

Solution :

ABCD is a square, here BD is the diagonal of the square.

BD2 = AB2 + AD2

BD2 = 152 + 152

BD2 = 450

BD = 15√2

Area of square BDEF = BD2

= (15√2)2

= 225(2)

= 450

Problem 8 :

In the figure, ABCD is a square. If ∠DPC = 80°, then find the value of x.

geo-properties-of-square-q1

Solution :

Given that ∠DPC = 80°, then ∠APL = 80°

Since AC is the diagonal, then ∠CAL = 45°(angle bisector)

In triangle APL, ∠PLB = x (exterior angle)

x = ∠PAL + ∠APL

x = 45 + 80

= 125

Problem 9 :

In the figure ABCD is a square and CDE is an equilateral triangle. find 

(i) ∠AED      ii) ∠EAB      iii)  Reflex of ∠AEC

geo-properties-of-square-q2

Solution :

(i) ∠AED

Triangle CDE is an equilateral triangle, ∠CDE = 60

∠EDA = 90 - 60 ==> 30

DA = DE, then 180 - 30 ==> 150

∠DEA  = 150/2 ==> 75

ii) 

∠EAB = 90 - 75 ==> 15

∠BCE = 90 - 60 ==> 30

iii) 

In a quadrilateral, the sum of interior angles is 360 degree.

∠EAB + ∠AEC + ∠ECB + ∠CBA = 360

15 + ∠AEC + 30 + 90 = 360

∠AEC + 135 = 360

∠AEC = 360 - 135

= 225

Problem 10 :

ABCD is a square, diagonal AC is joined. Then the measurement of ∠CAB is

(a) 35°       (b) 40°          (c) 45°          (d) 50°

Solution :

Diagonals will be angle bisectors. Then,  ∠CAB = 45°

Problem 11 :

Choose the most appropriate alternative for the given statement:

A square’s diagonals are _________ to each other.

a) Equal     b) Unequal      c) Parallel      d) None of the above

Solution :

Diagonals will be equal in square and in rectangle.

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