# PRE CALCULUS PROBLEMS AND SOLUTIONS(Part - 3)

Problem 1 :

If log 2 = 0.3010 and log 3 = 0.4771, then the value of log 24 is :

A)  1.0791

B)  1.7323

C)  1.3801

D)  1.8301

Solution :

Problem 2 :

The value of log (13 + 23 + 33 +……… + n3) is equal to :

A)  3 log 1 + 3 log 2 + …. 3 log n

B)  2 log n + 2 log (n + 1) – 2 log 2

C)  log n + log (n + 1) + log (2n + 1) – log 6

D)  1

Solution :

Problem 3 :

If px = q, qy = r and rz = p6, then the value of xyz will be :

A)  0

B)  1

C)  3

D)  6

Solution :

Problem 4 :

A)  2xy

B)  4xy

C)  2x2y2

D)  6xy

Solution :

Problem 5 :

A)  0

B)  1

C)  5

D)  60

Solution :

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Pre-Calculus Problems and Solutions (Part - 7)

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