Problem 1 :
If log 2 = 0.3010 and log 3 = 0.4771, then the value of log 24 is :
A) 1.0791
B) 1.7323
C) 1.3801
D) 1.8301
Solution :
Problem 2 :
The value of log (13 + 23 + 33 +……… + n3) is equal to :
A) 3 log 1 + 3 log 2 + …. 3 log n
B) 2 log n + 2 log (n + 1) – 2 log 2
C) log n + log (n + 1) + log (2n + 1) – log 6
D) 1
Solution :
Problem 3 :
If px = q, qy = r and rz = p6, then the value of xyz will be :
A) 0
B) 1
C) 3
D) 6
Solution :
Problem 4 :
A) 2xy
B) 4xy
C) 2x2y2
D) 6xy
Solution :
Problem 5 :
A) 0
B) 1
C) 5
D) 60
Solution :
Pre-Calculus Problems and Solutions (Part - 1)
Pre-Calculus Problems and Solutions (Part - 2)
Pre-Calculus Problems and Solutions (Part - 3)
Pre-Calculus Problems and Solutions (Part - 4)
Pre-Calculus Problems and Solutions (Part - 5)
Pre-Calculus Problems and Solutions (Part - 6)
Pre-Calculus Problems and Solutions (Part - 7)
Pre-Calculus Problems and Solutions (Part - 8)
Pre-Calculus Problems and Solutions (Part - 9)
Pre-Calculus Problems and Solutions (Part - 10)
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