POWERS OF 10 AND SCIENTIFIC NOTATION WORKSHEET

Problem 1 : 

Find the value : 

10-3

Problem 2 : 

Find the value : 

102

Problem 3 : 

Find the value : 

100

Problem 4 : 

Write the following number as a power of 10.

10,000,000

Problem 5 : 

Write the following number as a power of 10.

0.001

Problem 6 : 

Find the value : 

10

Problem 7 : 

Find the value of the expression.

89.74 x 106

Problem 8 : 

Find the value of the expression.

28.4 x 10-4

Problem 9 : 

Jupiter has a diameter of about 143,000 km. Its shortest distance from Earth is about 5.91 x 10km, and its average distance from the Sun is about 778,400,000 km. Jupiter's orbital speed is approximately 1.3 x 104 m/s. 

(i) Write Jupiter's diameter in scientific notation.

(ii) Write Jupiter's shortest distance from Earth in standard form. 

(iii) Write Jupiter's average distance from the Sun in scientific notation. 

(iii) Write Jupiter's orbital speed in standard form. 

Problem 10 :

Order the following list of numbers from least to greatest.

1.2x10-1, 8.2x104, 6.2x105, 2.4x105, 1x10-1, 9.9x10-4 

Detailed Answer Key

Problem 1 : 

Find the value : 

10-3

Solution :

=  10-3

The exponent is negative 3. So, start with 1 and move the decimal point three places to the left.

=  0.001

Problem 2 : 

Find the value : 

102

Solution :

=  102

The exponent is positive 2. So, start with 1 and move the decimal point two places to the right.

=  100

Problem 3 : 

Find the value : 

100

Solution :

=  100

The exponent is zero. So, start with 1 and move the decimal point zero places. 

=  1

Problem 4 : 

Write the following number as a power of 10.

10,000,000

Solution :

=  10,000,000

The decimal point is seven places to the right of 1.

So, the exponent is 7.

=  107

Problem 5 : 

Write the following number as a power of 10.

0.001

Solution :

=  0.001

The decimal point is three places to the left of 1.

So, the exponent is -3.

=  10-3

Problem 6 : 

Find the value : 

10

Solution :

=  10

The decimal point is one place to the right of 1.

So, the exponent is 1.

=  101

Problem 7 : 

Find the value of the expression.

89.74 x 106

Solution :

=  89.74 x 106

The exponent is positive 6.

So, move the decimal point six places to the right.

=  89,740,000

Problem 8 : 

Find the value of the expression.

28.4 x 10-4

Solution :

=  28.4 x 10-4

The exponent is negative 4.

So, move the decimal point four places to the left.

=  0.00284

Problem 9 : 

Jupiter has a diameter of about 143,000 km. Its shortest distance from Earth is about 5.91 x 10km, and its average distance from the Sun is about 778,400,000 km. Jupiter's orbital speed is approximately 1.3 x 104 m/s. 

(i) Write Jupiter's diameter in scientific notation.

(ii) Write Jupiter's shortest distance from Earth in standard form. 

(iii) Write Jupiter's average distance from the Sun in scientific notation. 

(iii) Write Jupiter's orbital speed in standard form. 

Solution :

Jupiter's diameter in scientific notation :

=  143,000

The decimal point has to be moved 5 places to the left to get a number between 1 and 10.

Then, 

=  1.43 x 10km

Jupiter's shortest distance from Earth in standard form :

=  5.91 x 108

The exponent is positive 8.

So, move the decimal point eight places to the right.

=  591000000 km

Jupiter's average distance from the Sun in scientific notation :

=  778,400,000

The decimal point has to be moved 8 places to the left to get a number between 1 and 10.

Then, 

=  7.784 x 108

Jupiter's orbital speed in standard form :

1.3 x 104

The exponent is positive 4.

So, move the decimal point four places to the right.

=  13,000 m/s

Problem 10 :

Order the following list of numbers from least to greatest.

1.2x10-1, 8.2x104, 6.2x105, 2.4x105, 1x10-1, 9.9x10-4 

Solution :

Step 1 : 

List the numbers in order by powers of 10.

9.9x10-4, 1.2x10-1, 1x10-1, 8.2x104, 6.2x105, 2.4x105

Step 2 : 

Order the numbers that have the same powers of 10.

9.9x10-4, 1x10-1, 1.2x10-1, 8.2x104, 2.4x105, 6.2x105

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