1. Add : (5x2 + 4x + 1) + (2x2 + 5x + 2)
2. Subtract (2x2 + 2y2 - 6) from (3x2 - 7y2 + 9).
3. Multiply : (3x3)(6x4)
4. Multiply using distributive property : (x + 3)(x - 6)
5. Multiply using FOIL method : (x + 4)(x + 5)
6. Multiply : 5(3x2 + 5x + 7)
7. Multiply : (x + 3)(x2 - 5x + 7)
8. Divide (x3 - 4x2 + 6x) by x, where x ≠ 0.
9. Divide (x2 - 9) by (x - 3), where x ≠ 3.
10. Find the quotient and the remainder when the polynomial (5x2 - 7x + 2) is divided by (x - 1), using long division.
11. (x2 y - 3y2 + 5xy2) - (-x2y + 3xy2 - 3y2)
which of the following is equivalent to the expression above.
a) 4x2y2 b) 8xy2 - 6y2 c) 2x2y + 2xy2
d) 2x2 y - 6y2
12. For a polynomial p(x), the value of p(3) is -2. Which of the following must be true about p(x) ?
a) x - 5 is a factor of p(x)
b) x - 2 is a factor of p(x)
c) x + 2 is a factor of p(x)
d) The remainder when p(x) is divided by x - 3 is -2.
13. 9a4 + 12a2 b2 + 4b4
which of the following is equivalent to the expression shown above ?
a) (3a2 + 2b2)2 b) (3a + 2b)4 c) (9a2 + 4b2)2
d) (9a + 4b)4
14. 2x(2x + 5) + 3(3x + 5) = ax2 + bx + c
In the equation above, a, b and c are constants, if the equation is true for all values of x, what is the value of b ?
1. Answer :
Associative and Commutative Properties can be used to regroup the like terms together and combine them as shown below.
= (5x2 + 4x + 1) + (2x2 + 5x + 2)
= (5x2 + 2x2) + (4x + 5x) + (1 + 2)
= 7x2 + 9x + 3
2. Answer :
= (3x2 - 7y2 + 9) - (2x2 + 2y2 - 6)
Distributive Property.
= 3x2 - 7y2 + 9 - 2x2 - 2y2 + 6
Group like terms together.
= (3x2 - 2x2) + (-7y2 - 2y2) + (9 + 6)
Combine like terms.
= x2 - 9y2 + 15
3. Answer :
= (3x3)(6x4)
Group factors with like bases together.
= (3 ⋅ 6)(x3 ⋅ x4)
Use the Product of Powers Property.
= 18x3 + 4
= 18x7
4. Answer :
= (x + 3)(x - 6)
Distribute.
= x(x - 6) + 3(x - 6)
Distribute again.
= x(x) + x(-6) + 3(x) + 3(-6)
Multiply.
= x2 - 6x + 3x - 18
Combine like terms.
= x2 - 3x - 18
5. Answer :
Multiply the First terms :
(x + 4)(x + 5) ---> x ⋅ x = x2
Multiply the Outer terms :
(x + 4)(x + 5) ---> x ⋅ 5 = 5x
Multiply the Inner terms :
(x + 4)(x + 5) ---> 4 ⋅ x = 4x
Multiply the Last terms :
(x + 4)(x + 5) ---> 4 ⋅ 5 = 20
(x + 4)(x + 5) = x2 + 5x + 4x + 20
(x + 4)(x + 5) = x2 + 9x + 20
6. Answer :
= 5(3x2 + 5x + 7)
Distribute 2.
= 5(3x2) + 5(5x) + 5(7)
Multiply.
= 15x2 + 25x + 35
7. Answer :
= (x + 3)(x2 - 5x + 7)
Distributive.
= x(x2 - 5x + 7) + 3(x2 - 5x + 7)
Distribute again.
= x(x2) + x(-5x) + x(7) + 3(x2) + 3(-5x) + 3(7)
Simplify.
= x3 - 5x2 + 7x + 3x2 - 15x + 21
Combine the like terms.
= x3 - 5x2 + 3x2+ 7x - 15x + 21
= x3 - 2x2 - 8x + 21
8. Answer :
= (x3 - 4x2 + 6x)/x
= x3/x - 4x2/x + 6x/x
= x2 - 4x + 6
9. Answer :
= (x2 - 9)/(x - 3)
= (x2 - 32)/(x - 3)
Using the algebraic identity a2 - b2 = (a + b)(a - b) to factor (x2 - 32).
= [(x + 3)(x - 3)]/(x - 3)
= x + 3
10. Answer :
Quotient = 5x - 2
Remainder = 0
11. Answer :
= (x2 y - 3y2 + 5xy2) - (-x2y + 3xy2 - 3y2)
Distributing negative, we get
= x2 y - 3y2 + 5xy2 + x2y - 3xy2 + 3y2
Combining the like terms, we get
= x2 y + x2y - 3y2 + 3y2 + 5xy2 - 3xy2
= 2x2 y + 2xy2
So, option c is correct.
12. Answer :
For a polynomial p(x),
when p(1) = 0 then x = 1 is a solution or zero.
When p(1) = a, then x = 1 is not a solution and dividing the polynomial by x - 1 we get the remainder a.
So, option d is correct.
13. Answer :
= 9a4 + 12a2 b2 + 4b4
= 32(a2) 2 + 12a2 b2 + 22(b2)2
= (3a2) 2 + 12a2 b2 + (2b2)2
= (3a2) 2 + 2(3a2) (2b2) + (2b2)2
Looks like an algebraic identity a2 + 2ab + b2
= (3a2 + 2b2)2
14. Answer :
2x(2x + 5) + 3(3x + 5) = ax2 + bx + c
Using distributive property,
4x2 + 10x + 9x + 15 = ax2 + bx + c
Combining the like terms, we get
4x2 + 19x + 15 = ax2 + bx + c
Comparing the corresponding terms
a = 4, b = 19 and c = 15
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