NATURE OF THE ROOTS OF A QUADRATIC EQUATION WORKSHEET

About "Nature of the Roots of a Quadratic Equation Worksheet"

Nature of the Roots of a Quadratic Equation Worksheet :

Worksheet given in this section will be much useful to the students who would like to practice problems on nature of the roots of a quadratic equation. 

Before look at the worksheet, if you would like to know the stuff related to nature of the roots to a quadratic equation, 

Please click here

Nature of the Roots of Quadratic Equation Worksheet - Problems

Problem 1 :

Examine the nature of the roots of the following quadratic equation.

x² + 5x + 6  =  0

Problem 2 :

Examine the nature of the roots of the following quadratic equation.

2x² - 3x - 1  =  0 

Problem 3 :

Examine the nature of the roots of the following quadratic equation.

x² - 16x + 64  =  0

Problem 4 :

Examine the nature of the roots of the following quadratic equation.

3x² + 5x + 8  =  0

Problem 5 :

If the roots of the equation 2x² + 8x - m³ = 0 are equal, then find the value of m. 

Problem 6 :

If the roots of the equation x² - (p + 4)x + 2p + 5  =  0 are equal, then find the value of p. 

Problem 7 :

If the roots of the equation x² + (2s - 1)x + s²  =  0 are real, then find the value of a. 

Problem 8 :

If the roots of the equation x² - 16x + k  =  0 are real and equal, then find the value of k.

Problem 9 :

Examine the nature of the roots of the following quadratic equation.

x² - 5x  =  2(5x + 1)

Problem 10 : 

Examine the nature of the roots of the following quadratic equation.

1/(x+1)  +  2/(x-4)  =  2

Nature of the Roots of Quadratic Equation Worksheet - Solutions

Problem 1 :

Examine the nature of the roots of the following quadratic equation.

x² + 5x + 6  =  0

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  5 and c  =  6.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  5² - 4(1)(6)

b² - 4ac  =  25 - 24

b² - 4ac  =  1 

Here, b² - 4ac > 0 and also a perfect square. 

So, the roots are real, unequal and rational.  

Problem 2 :

Examine the nature of the roots of the following quadratic equation.

2x² - 3x - 1  =  0 

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  2, b  =  -3 and c  =  -1.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  (-3)² - 4(2)(-1)

b² - 4ac  =  9 + 8

b² - 4ac  =  17 

Here, b² - 4ac > 0, but not a perfect square. 

So, the roots are real, unequal and irrational.  

Problem 3 :

Examine the nature of the roots of the following quadratic equation.

x² - 16x + 64  =  0

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  -16 and c  =  64.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  (-16)² - 4(1)(64)

b² - 4ac  =  256 - 256

b² - 4ac  =  0 

So, the roots are real, equal and rational.  

Problem 4 :

Examine the nature of the roots of the following quadratic equation.

3x² + 5x + 8  =  0

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  3, b  =  5 and c  =  8.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  5² - 4(3)(8)

b² - 4ac  =  25 + 96

b² - 4ac  =  121 

Here, b² - 4ac > 0 and also a perfect square. 

So, the roots are real, unequal and rational.  

Problem 5 :

If the roots of the equation 2x² + 8x - m³ = 0 are equal, then find the value of m. 

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  2, b  =  8 and c  =  -m³.

Because the roots of the given equation are equal, 

b² - 4ac  =  0

8² - 4(2)(-m³)  =  0

64 + 8m³  =  0

Subtract 64 from each side. 

8m³  =  -64

Divide each side by 8.

m³  =  -8

m³  =  (-2)³

m  =  -2.  

So, the value of m is -2. 

Problem 6 :

If the roots of the equation x² - (p + 4)x + 2p + 5  =  0 are equal, then find the value of p. 

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  -(p + 4) and c  =  (2p + 5).

Because the roots of the given equation are equal, 

b² - 4ac  =  0

[-(p + 4)]² - 4(1)(2p + 5)  =  0

Simplify.

(p + 4)² - 4(2p + 5)  =  0

p² + 8p + 16 -8p -20  =  0

p² - 4  =  0

p² - 2²  =  0

(p + 2)(p - 2)  =  0

p + 2  =  0     or     p - 2  =  0

p  =  -2     or     p  =  2

So, the value of p is ±2.

Problem 7 :

If the roots of the equation x² + (2s - 1)x + s²  =  0 are real, then find the value of a. 

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  (2s - 1) and c  =  s².

Because the roots of the given equation are equal, 

b² - 4ac  ≥  0

(2s - 1)² - 4(1)(s²)  ≥  0

Simplify.

4s² - 4s + 1 - 4s²  ≥  0

-4s + 1  ≥  0

-4s  ≥  -1

Divide each side by -4. 

s  ≤  1/4

So, the value of s is less than or equal to 1/4. 

Note : 

Whenever we multiply or divide both sides of an inequality by a negative number, we have to flip the inequality sign. 

Problem 8 :

If the roots of the equation x² - 16x + k  =  0 are real and equal, then find the value of k.

Solution :

The given quadratic equation is in the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  -16 and c  =  k.

Because the roots of the given equation are equal, 

b² - 4ac  =  0

(-16)² - 4(1)(k)  =  0

256 - 4k  =  0

Subtract 256 from each side. 

-4k  =  -256

Divide each side by -4.

k  =  64

So, the value of k is 64. 

Problem 9 :

Examine the nature of the roots of the following quadratic equation.

x² - 5x  =  2(5x + 1)

Solution :

The given quadratic equation is not in the general form.

First, write the given quadratic equation in the general form. 

x² - 5x  =  2(5x + 1)

x² - 5x  =  10x + 2

x² - 15x - 2  =  0

Now, the quadratic equation is the general form

ax² + bx + c  =  0

Then, we have a  =  1, b  =  -15 and c  =  -2.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  (-15)² - 4(1)(-2)

b² - 4ac  =  225 + 8

b² - 4ac  =  233 

Here, b² - 4ac > 0, but not a perfect square. 

So, the roots are real, unequal and irrational.  

Problem 10 : 

Examine the nature of the roots of the following quadratic equation.

1/(x+1)  +  2/(x-4)  =  2

Solution :

The given quadratic equation is not in the general form.

First, write the given quadratic equation in the general form. 

1/(x+1)  +  2/(x-4)  =  2

Add the two fractions on the right side of the equation using cross multiplication. 

[(x-4) + 2(x+1)] / [(x+1)(x-4)]  =  2

(x - 4 + 2x + 2) / (x² - 3x - 4)  =  2

(3x - 2) / (x² - 3x - 4)  =  2

Multiply each side by (x² - 3x - 4). 

3x - 2  =  2(x² - 3x - 4)

3x - 2  =  2x² - 6x - 8

2x² - 9x - 6  =  0

Now, the quadratic equation is the general form

ax² + bx + c  =  0

Then, we have a  =  2, b  =  -9 and c  =  -6.

Find the value of the discriminant b² - 4ac. 

b² - 4ac  =  (-9)² - 4(2)(-6)

b² - 4ac  =  81 + 48

b² - 4ac  =  129

Here, b² - 4ac > 0, but not a perfect square. 

So, the roots are real, unequal and irrational.  

After having gone through the stuff given above, we hope that the students would have understood, "Nature of the Roots of a Quadratic Equation". 

Apart from the stuff given in this section,  if you need any other stuff in math, please use our google custom search here.

You can also visit our following web pages on different stuff in math. 

WORD PROBLEMS

HCF and LCM  word problems

Word problems on simple equations 

Word problems on linear equations 

Word problems on quadratic equations

Algebra word problems

Word problems on trains

Area and perimeter word problems

Word problems on direct variation and inverse variation 

Word problems on unit price

Word problems on unit rate 

Word problems on comparing rates

Converting customary units word problems 

Converting metric units word problems

Word problems on simple interest

Word problems on compound interest

Word problems on types of angles 

Complementary and supplementary angles word problems

Double facts word problems

Trigonometry word problems

Percentage word problems 

Profit and loss word problems 

Markup and markdown word problems 

Decimal word problems

Word problems on fractions

Word problems on mixed fractrions

One step equation word problems

Linear inequalities word problems

Ratio and proportion word problems

Time and work word problems

Word problems on sets and venn diagrams

Word problems on ages

Pythagorean theorem word problems

Percent of a number word problems

Word problems on constant speed

Word problems on average speed 

Word problems on sum of the angles of a triangle is 180 degree

OTHER TOPICS 

Profit and loss shortcuts

Percentage shortcuts

Times table shortcuts

Time, speed and distance shortcuts

Ratio and proportion shortcuts

Domain and range of rational functions

Domain and range of rational functions with holes

Graphing rational functions

Graphing rational functions with holes

Converting repeating decimals in to fractions

Decimal representation of rational numbers

Finding square root using long division

L.C.M method to solve time and work problems

Translating the word problems in to algebraic expressions

Remainder when 2 power 256 is divided by 17

Remainder when 17 power 23 is divided by 16

Sum of all three digit numbers divisible by 6

Sum of all three digit numbers divisible by 7

Sum of all three digit numbers divisible by 8

Sum of all three digit numbers formed using 1, 3, 4

Sum of all three four digit numbers formed with non zero digits

Sum of all three four digit numbers formed using 0, 1, 2, 3

Sum of all three four digit numbers formed using 1, 2, 5, 6