Let f : A -> B be a function. The function f is called an one-one function if it takes different elements of A into different elements of B
Another name for one-to-one function is injective function.
To prove a function f : A → B to be one-to-one, it is enough to prove any one of the following :
A function f : A → B is said to be one-to-one if x, y ∈ A,
x ≠ y ⇒ f(x) ≠ f(y)
[or equivalently f(x) = f(y) ⇒ x = y]
The following statements are some important simple results.
Let A and B be two sets with m and n elements.
(i) There is no one-to-one function from A to B if m > n.
(ii) If there is an one-to-one function from A to B, then m ≤ n.
Example 1 :
Check whether the following function is one-to-one
f : N → N defined by f(n) = n + 2
Solution :
To check if the given function is one to one, let us apply the rule
f (x) = f (y) ----> x = y
f(x) = x + 2 and f(y) = y + 2
x + 2 = y + 2
x = y
For every element if set N has images in the set N.
Hence it is one to one function.
Example 2 :
Check whether the following function is one-to-one
f : R → R defined by f(n) = n2
Solution :
To check if the given function is one to one, let us apply the rule
f(x) = f(y) ----> x = y
f(x) = x2 and f(y) = y2
By equating f(x) and f(y), we get
x2 = y2
x = y
From this we cannot decide that the function is one to one. Because every two different elements in the domain has same images is co-domain. That is,
If x = 1 then y = 1. If x = -1 also, then y is 1.
Hence the given function is not one to one.
Example 3 :
Check whether the following function is one-to-one
f : R - {0} → R defined by f(x) = 1/x
Solution :
To check if the given function is one to one, let us apply the rule
f(x) = f(y) ----> x = y
f(x) = 1/x and f(y) = 1/y
By applying the above rule, we get
1/x = 1/y
x = y
Every element in domain has different images in co-domain.
Hence it is one to one function.
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